In the following problem, check that it is appropriate to use the normal approximation to the binomial. Then use the normal distribution to estimate the requested probabilities. Do you take the free samples offered in supermarkets? About 64% of all customers will take free samples. Furthermore, of those who take the free samples, about 33% will buy what they have sampled. Suppose you set up a counter in a supermarket offering free samples of a new product. The day you were offering free samples, 311 customers passed by your counter. (Round your answers to four decimal places.) (a) What is the probability that more than 180 will take your free sample? (b) What is the probability that fewer than 200 will take your free sample? 0.4602 (c) What is the probability that a customer will take a free sample and buy the product? Hint: Use the multiplication rule for dependent events. Notice that we are given the conditional probability P(buy|sample) = 0.33, while P(sample) = 0.64. (d) What is the probability that between 60 and 80 customers will take the free sample and buy the product? Hint: Use the probability of success calculated in part (c).

College Algebra
7th Edition
ISBN:9781305115545
Author:James Stewart, Lothar Redlin, Saleem Watson
Publisher:James Stewart, Lothar Redlin, Saleem Watson
Chapter9: Counting And Probability
Section9.3: Binomial Probability
Problem 2E: If a binomial experiment has probability p success, then the probability of failure is...
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In the following problem, check that it is appropriate to use the normal approximation to the binomial. Then use the normal
distribution to estimate the requested probabilities.
Do you take the free samples offered in supermarkets? About 64% of all customers will take free samples. Furthermore, of those who
take the free samples, about 33% will buy what they have sampled. Suppose you set up a counter in a supermarket offering free
samples of a new product. The day you were offering free samples, 311 customers passed by your counter. (Round your answers to
four decimal places.)
(a) What is the probability that more than 180 will take your free sample?
(b) What is the probability that fewer than 200 will take your free sample?
0.4602
(c) What is the probability that a customer will take a free sample and buy the product? Hint: Use the multiplication rule for
dependent events. Notice that we are given the conditional probability P(buy|sample) = 0.33, while P(sample) = 0.64.
(d) What is the probability that between 60 and 80 customers will take the free sample and buy the product? Hint: Use the
probability of success calculated in part (c).
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Transcribed Image Text:In the following problem, check that it is appropriate to use the normal approximation to the binomial. Then use the normal distribution to estimate the requested probabilities. Do you take the free samples offered in supermarkets? About 64% of all customers will take free samples. Furthermore, of those who take the free samples, about 33% will buy what they have sampled. Suppose you set up a counter in a supermarket offering free samples of a new product. The day you were offering free samples, 311 customers passed by your counter. (Round your answers to four decimal places.) (a) What is the probability that more than 180 will take your free sample? (b) What is the probability that fewer than 200 will take your free sample? 0.4602 (c) What is the probability that a customer will take a free sample and buy the product? Hint: Use the multiplication rule for dependent events. Notice that we are given the conditional probability P(buy|sample) = 0.33, while P(sample) = 0.64. (d) What is the probability that between 60 and 80 customers will take the free sample and buy the product? Hint: Use the probability of success calculated in part (c). Need Help? Read It Watch It Master It
Expert Solution
Step 1: Introduction and part a)

n=311p=0.64

np=199.04>10n(1-p)=111.96>10

Since both np and n(1-p) are greater than 10, hence normal approximation can be used.

a) Let X be the random variable which denote the number of  customer that is take free samples.

mean=μ=np=199.04standard deviation =σ=np(1-p)=8.4649

The required probability is

 PX>180=PX-μσ>180-199.048.4649                    =PZ>-2.2492                    =0.9878

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