In the formula for capacitance C-- -, variable d represents: Kto A d Select one O separation between the plates of the capacitor O area of the metal plates that make up the capacitor for this experiment. O is the permittivity constant. O is the dielectric constant of the insulating material between the plates. When two capacitor plates are connected to a potential difference V, Select one: O None of the above

In the formula for capacitance C-- -, variable d represents: Kto A d Select one O separation between the plates of the capacitor O area of the metal plates that make up the capacitor for this experiment. O is the permittivity constant. O is the dielectric constant of the insulating material between the plates. When two capacitor plates are connected to a potential difference V, Select one: O None of the above

University Physics Volume 2

18th Edition

ISBN:9781938168161

Author:OpenStax

Publisher:OpenStax

Chapter8: Capacitance

Section: Chapter Questions

Problem 53P: A parallel-plate capacitor has charge of magnitude 9.00F on each plate and capacitance 3.00F when...

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A parallel-plate capacitor has charge of magnitude 9.00F on each plate and capacitance 3.00F when there is air between the plates. The plates are separated by 2.00 mm. With the charge on the plates kept constant, a dielectric with =5 . is inserted between the plates, completely filling the volume between the plates, (a) What is the potential difference between the plates of the capacitor, before and after the dielectric has been inserted? (b) What is the electrical field at the point midway between the plates before and after the dielectric is inserted?
When a 360-nF air capacitor is connected to a power supply, the energy stored in the capacitor is 18.5J . While the capacitor is connected to the power supply, a slab of dielectric is insetted that completely fills die space between the plates. This increases the stored energy by 23.2J . (a) What is the potential difference between the capacitor plates? (b) What is die dielectric constant of the slab?
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A capacitor is constructed from two square, metallic plates of sides and separation d. Charges +Q and Q are placed on the plates, and the power supply is then removed. A material of dielectric constant K is inserted a distance x into the capacitor as shown in Figure P20.85. Assume d is much smaller than x. (a) Find the equivalent capacitance of the device. (b) Calculate the energy stored in the capacitor. (c) Find the direction and magnitude of the force exerted by the plates on the dielectric. (d) Obtain a numerical value for the force when x = /2, assuming = 5.00 cm, d = 2.00 mm, the dielectric is glass ( = 4.50), and the capacitor was charged to 2.00 103 V before the dielectric was inserted. Suggestion: The system can be considered as two capacitors connected in parallel. Figure P20.85