In the game of roulette, a player can place a $6 bet on the number 1 and have a 38 probability of winning. If the metal ball lands on 1, the play gets to keep the $6 paid to play the game and the player is awarded an additional $210. Otherwise, the player is awarded nothing and the casin takes the player's $6. Find the expected value E(x) to the player for one play of the game. If x is the gain to a player in a game of chance, then is usually negative. This value gives the average amount per game the player can expect to lose. The expected value is $. (Round to the nearest cent as needed.)

College Algebra
7th Edition
ISBN:9781305115545
Author:James Stewart, Lothar Redlin, Saleem Watson
Publisher:James Stewart, Lothar Redlin, Saleem Watson
Chapter9: Counting And Probability
Section9.3: Binomial Probability
Problem 2E: If a binomial experiment has probability p success, then the probability of failure is...
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In the game of roulette, a player can place a $6 bet on the number 1 and have a probability of winning. If the metal ball lands on 1, the player
38
gets to keep the $6 paid to play the game and the player is awarded an additional $210. Otherwise, the player is awarded nothing and the casino
takes the player's $6. Find the expected value E(x) to the player for one play of the game. If x is the gain to a player in a game of chance, then E(x)
is usually negative. This value gives the average amount per game the player can expect to lose.
The expected value is $.
(Round to the nearest cent as needed.)
Transcribed Image Text:In the game of roulette, a player can place a $6 bet on the number 1 and have a probability of winning. If the metal ball lands on 1, the player 38 gets to keep the $6 paid to play the game and the player is awarded an additional $210. Otherwise, the player is awarded nothing and the casino takes the player's $6. Find the expected value E(x) to the player for one play of the game. If x is the gain to a player in a game of chance, then E(x) is usually negative. This value gives the average amount per game the player can expect to lose. The expected value is $. (Round to the nearest cent as needed.)
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