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- What is the mechanism for step 4Suppose the formation of tert-butanol proceeds by the following mechanism: step elementary reaction rate constant 1 CH33CBr (aq) → CH33C+ (aq) + Br− (aq) k1 2 CH33C+ (aq) + OH− (aq) → CH33COH (aq) k2 Suppose also k1 ≫ k2 . That is, the first step is much faster than the second.What is the mechanism of the first step?
- Within this reaction, provide two accurate sketches (one for Step 1, and the other after Step 2) as shown in the image attached.For which reaction mechanisms—SN1, SN2, E1, or E2—of thefollowing statement true? A statement may be true for one or moremechanisms. The reaction rate increases when the solvent is changed from CH3OHto (CH3)2SO.Which of the following are intermediates in the reaction below?
- What is the mechanism of the second step?How are the E1 and E1cB reaction mechanisms different from each other? Draw an example of the reaction mechanism for each one to help illustrate the answerFor 10.29, the trans product (major product) and the cis product (third product) are displayed as possible E2 products. However, for 10.30, only the trans product (major product) is shown. How come the cis product is not needed?