In this exercise, we instead consider a form of chemosynthesis. Chemosynthesis is for instance used by microorganisms, whose habitat has very little sunlight such as the deep sea. Here, we focus on chemosynthesis with sulphur, and the corresponding chemical reaction is ₁H₂S + ₂ CO₂ +£3O₂ → £4H₂O +25S+ Cm (H₂O)n. Once again, x, denote the coefficients that balance the equation. If we use the same pro- cedure as in exercise 1 on the reaction in (3), the reduced echelon form of the augmented matrix is 1000-1 0 0100 m 0010-1 -m 0001-1 -n (i) Write out the parametrized solution to the system of equations in (4). (ii) Can we - as in 1(iv) – find a unique solution whenever m and n are known? (iii) Do all solutions (in the mathematical sense) of the system (4) correspond to useable solutions in terms of the chemical equation (3)? 0

In this exercise, we instead consider a form of chemosynthesis. Chemosynthesis is for instance used by microorganisms, whose habitat has very little sunlight such as the deep sea. Here, we focus on chemosynthesis with sulphur, and the corresponding chemical reaction is ₁H₂S + ₂ CO₂ +£3O₂ → £4H₂O +25S+ Cm (H₂O)n. Once again, x, denote the coefficients that balance the equation. If we use the same pro- cedure as in exercise 1 on the reaction in (3), the reduced echelon form of the augmented matrix is 1000-1 0 0100 m 0010-1 -m 0001-1 -n (i) Write out the parametrized solution to the system of equations in (4). (ii) Can we - as in 1(iv) – find a unique solution whenever m and n are known? (iii) Do all solutions (in the mathematical sense) of the system (4) correspond to useable solutions in terms of the chemical equation (3)? 0

General Chemistry - Standalone book (MindTap Course List)

11th Edition

ISBN:9781305580343

Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell

Publisher:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell

Chapter6: Thermochemisty

Section6.3: Heat Of Reaction; Enthalpy Of Reaction

Problem 6.4E: Consider the combustion (burning) of methane, CH4, in oxygen. CH4(g)+2O2(g)CO2(g)+2H2O(l) The heat...

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Course: Logical MathematicsFran and Juan Carlos have finished analysis of 112.5 GRAMS of sediments they collected at mouth of a river, and have spent 5 minutes for every 20 MILIGRAMS (MG) of minerals.How many MINUTES did they spend in total for 112.5 GRAMS? (Remember that 1 GRAM = 1,000 MG). Please details of procedure
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Trial #1: A piece of magnesium with a mass of 0.330 grams was placed into a solution of hydrochloric acid. 335 mL of hydrogen gas were produce when this reaction occurred at 22.0 °C and a pressure of 747.0 mmHg. Mg(s) + 2HCl(aq) ⟶⟶ H2(g) + MgCl2(aq) Calculate the molar volume (liters/mole) of hydrogen for Trial #1?
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Question 4. Practice exam. Will post the answer, just need help with the concept so please explain. Thank you!
trials. Firstly, the student used potassium hydrogen phthalate (KHP, 204.22 g/mol) as standard to determine the exact concentration of the NaOHtitrant. The results of the student are summarized in the table below:Note: The stoichiometric relationship of KHP to NaOH is 1:1Standardization Trial 1 Trial 2 Trial 3 Trial 4KHP Mass, g 0.5033 0.5066 0.6989 0.6843Volume NaOH used, mL 24.32 25.61 24.67 24.56After the standardization, the student weighed different amounts of the unknown acid. In a similar fashion, the student performed acid-base titrationusing phenolphthalein as indicator. The results of the molecular weight determination are summarized below:Note: The stoichiometric relationship of Unknown acid to NaOH is 1:2Molecular WeightDeterminationTrial 1 Trial 2 Trial 3 Trial 4Unknown Mass, g 0.1234 0.1034 0.1178 0.1322Volume NaOH used, mL 21.75 20.56 24.39 25.08The potential unknown given by the professor to the student are as follows:Diprotic acid Fumaric acid Oxalic acid Succinic acid…
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Answer key show work #35i 1.85 moles H2SO4 #35j 0.00836 moles of Ca3(PO4)2 molecules #35k 1.3333 moles H3PO4 (answer corrected 10/9/19) #35l 130.67 g H3PO4 (answer corrected 10/9/19)

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