   # ercise 9.5 In Example 9.6 we answered one of the questions we posed in the introduction to this chapter. Now let’s see if you can answer the other question posed there. Determine what mass of carbon monoxide and what mass of hydrogen are required to form 6.0 kg of methanol by the reaction :math&gt; CO ( g ) + 2 H 2 ( g ) → CH 3 OH ( l ) ### Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781337399425

#### Solutions

Chapter
Section ### Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781337399425
Chapter 9.3, Problem 9.5SC
Textbook Problem
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## ercise 9.5 In Example 9.6 we answered one of the questions we posed in the introduction to this chapter. Now let’s see if you can answer the other question posed there. Determine what mass of carbon monoxide and what mass of hydrogen are required to form 6.0 kg of methanol by the reaction:math> CO ( g ) + 2 H 2 ( g ) → CH 3 OH ( l )

Interpretation Introduction

Interpretation:

The mass of carbon monoxide mass of hydrogen required to produce 6.0 kg of methanol by the reaction should be calculated.

Concept Introduction:

The balanced chemical reaction of carbon monoxide and hydrogen to give methanol is as follows:

CO(g)+2H2(g)CH3OH(l)

The mass of carbon monoxide and hydrogen gas required can be calculated from their number of moles which can be calculated from number of moles of methanol.

### Explanation of Solution

From the balanced chemical reaction, 1 mol of carbon monoxide reacts with 2 mol of hydrogen gas to give 1 mol of methanol.

Calculate number of moles of methanol from mass of methanol as follows:

n=mM

Molar mass of methanol is 32.04 g/mol, putting the values,

n=6 kg(1000 g1 kg)32.04 g/mol=187.27 mol

1 moles of methanol obtained from 1 mol of carbon monoxide thus, 187.27 mol of methanol is obtained from 187.27 mol of carbon monoxide.

Since, 1 mole of carbon monoxide reacts with 2 moles of hydrogen gas thus, 187.27 mol of carbon monoxide reacts with 374.5 mol of hydrogen gas.

Converting number of moles to mass as follows:

For carbon monoxide:

m=n×M

Molar mass of carbon monoxide is 28.01 g/mol and number of moles is 187.27 mol thus, mass will be:

m=(187.27 mol)(28

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