#include #include main () { int array [3] [2] [2], value=0, i, j, k; int *p= (int *) array; for (i 0; i < 3; i++) { for(j = 0; j < 2; j++) { for (k = 0; k < 2; k++) array[i][j] [k] = value; value = value + 1; =
#include #include main () { int array [3] [2] [2], value=0, i, j, k; int *p= (int *) array; for (i 0; i < 3; i++) { for(j = 0; j < 2; j++) { for (k = 0; k < 2; k++) array[i][j] [k] = value; value = value + 1; =
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
Related questions
Question
![#include <stdio.h>
#include <stdlib.h>
main () {
int array [3] [2] [2], value=0, i, j, k;
int *p= (int *) array;
}
for (i = 0; i < 3; i++) {
for(j=
}
=
0; j < 2; j++) {
for (k = 0; k < 2; k++) {
array[i][j] [k] = value;
value = value + 1;
}
}
for (i = 0; i < 12; i++)
printf("%d ", p[i]);
printf("\n");
printf ("Examine memory now.\n");](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F227760bc-229e-461f-9ddd-fe24646c67a0%2F397bcf9f-a116-44ab-b1ce-37e7eb8bee4b%2Fgq7z6z_processed.png&w=3840&q=75)
Transcribed Image Text:#include <stdio.h>
#include <stdlib.h>
main () {
int array [3] [2] [2], value=0, i, j, k;
int *p= (int *) array;
}
for (i = 0; i < 3; i++) {
for(j=
}
=
0; j < 2; j++) {
for (k = 0; k < 2; k++) {
array[i][j] [k] = value;
value = value + 1;
}
}
for (i = 0; i < 12; i++)
printf("%d ", p[i]);
printf("\n");
printf ("Examine memory now.\n");
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