Information: Rats with one or two brown fur alleles are both phenotypically brown because brown is dominant. Rats with two Albino (white) alleles are phenotypically white. 2. Cross a heterozygous Brown male to a heterozygous Brown female Male parent genotype: Possible Sperm: Female parent genotype: Possible Eggs: offspring genotypes & ratios: offspring phenotypes & ratios:
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- A true-breeding rabbit with agouti (mottled, grayish brown) fur crossed with a true-breeding rabbit with chinchilla (silver) fur produces all agouti offspring. A true-breeding chinchilla rabbit crossed with a true-breeding Himalayan rabbit (white fur with pigmented nose, ears, tail, and legs) produces all chinchilla offspring. A true-breeding Himalayan rabbit crossed with a true-breeding albino rabbit produces all Himalayan offspring. Explain the inheritance of the fur colors.In cats, the genotype AA produces tabby fur color; Aa is also a tabby, and aa is black. Another gene at a different locus is epistatic to the gene for fur color. When present in its dominant W form (WW or Ww), this gene blocks the formation of fur color and all the offspring are white; ww individuals develop normal fur color. What fur colors, and in what proportions, would you expect from the cross AaWw Aa Ww?Consider a cross to investigate the pea pod texture trait, involving constricted or inflated pods. Mendel found that the traits behave according to a dominant/ recessive pattern in which inflated pods were dominant. If you performed this cross and obtained 650 inflated-pod plants in the F2 generation, approximately how many constricted-pod plants would you expect to have? 600 165 217 468
- If black and white true-breeding mice are mated and the result is all gray offspring, what inheritance pattern would this be indicative of? dominance codominance multiple alleles incomplete dominanceHow many different offspring genotypes are expected in a trihybrid cross between parents heterozygous for all three traits when the traits behave in a dominant and recessive pattern? How many phenotypes? 64 genotypes: 16 phenotypes 16 genotypes; 64 phenotypes 8 genotypes; 27 phenotypes 27 genotypes; 8 phenotypes1. In fruit flies, the phenotype for eye color is determined by a certain locus. E indicates the dominant allele and eindicates the recessive allele. The cross between a male wild-type fruit fly and a female white-eyed fruit flyproduced the following offspring.Wild-typeMaleWild-typeFemaleWhite-eyedMaleWhite-eyedFemaleBrown-eyedFemaleF1 0 45 55 0 1The wild-type and white-eyed individuals from the F1 generation were then crossed to produce the followingoffspring.F2 23 31 22 24 0(a) Determine the genotypes of the original parents (P generation) and explain your reasoning. You may usePunnett squares to enhance your description, but the results from the Punnett squares must be discussed inyour answer.(b) Use a Chi-squared test on the F2 generation data to analyze your prediction of the parental genotypes. Showall your work and explain the importance of your final answer.(c) The brown-eyed female in the F1 generation resulted from a mutational change. Explain what a mutation is,and discuss…
- 8. In certain breeds of dogs, two different sets of alleles determine the color pattern. Black color is dominant and red color is recessive; solid color is dominant and white spotting is recessive. A homozygous black-and-white spotted male is crossed with a red-and-white spotted female. What is the probability of their producing a solid black puppy? Show your work.4. In cattle, roan coat color is an example of an autosomal, co-dominant phenotype. Roan (CrCw) cattle are produced from the mating of a white (CwCw) cow to a red cow (CrCr). Predict the phenotypic and genotypic frequencies of offspring from each of the following crosses: 1. Roan x White 3. Red x White 2. Roan x Red 4. Roan x Roan1. In humans, widow’s peak (W) is dominant over having a straight hairline (w). If a homozygous man with a widow’s peak has a child with a woman with a straight hairline, what are the odds the child will have a widow’s peak? Show work. 2. Ellis-van Creveld syndrome is a recessive inherited condition that results in 6-fingered dwarfism. Two parents without this condition have with Ellis-van Creveld syndrome. What are the genotypes of the parents and offspring? What are the odds that the son will have a 6-fingered child if his partner is a woman who is heterozygous for the condition? Show work. 3. The gene for dangling earlobes is dominant over the gene for attached earlobes. A woman with attached earlobes has a child with a man with dangling earlobes whose mother had attached earlobes. What is the probability that this child will have attached lobes? Show work. 4. In humans, normal pigmentation is due to a dominant gene, while albinism is recessive. A normally pigmented man has a…
- 7. The ability to roll your tongue (R) is dominant to lack of this ability (r). A. What is the genotype of a man who can roll his tongue if his father couldn’t? B. If a man who is heterozygous for tongue rolling marries a woman who is heterozygous, what would you predict for the genotypes and phenotypes of their children?7) Skin color is a complex trait and while just a few genes account for the major difference between light and dark skin color, dozens of other genes participate. Assume in this hypothetical scenario there are only two genes for skin color, A and B. Each gene exhibits incomplete dominance. AABB (homozygous dominant for both genes) results in the darkest skin color and aabb (homozygous recessive for both genes) results in the lightest skin color. Tomas is heterozygous for both genes; his partner, Helga, is heterozygous for the A gene and homozygous recessive for the B gene. Construct a Punnett Square showing the cross of this couple. What are the expected genotypes and phenotypes of the children this couple could have?4. The inheritance of coat colour in cattle controlled by multiple alleles with a dominance hierarchy as follows: S > sh > sc > s. The S allele produces a white band all over the cattle’s body known as ‘Dutch band’, the sh allele produces spots on the skin known as ‘Hereford’, the sc allele produces solid colour, and the s allele produces ‘Holstein’ spots. Homozygous ‘Dutch band’ males are cross to ‘Holstein’ females. The F1 females are crossed to ‘Hereford’ males of the shsc genotype. With the aid of genetic diagram, determine the expected genotypic and phenotypic frequencies in the F2 progeny.