Initial velocity =uhAngle offire eTime of flight to apex of trajectory (uSinegTotal time of flight t = (2usinoygRange to apex of trajectory (u'Sin20y2gTotal range s- (uSin20MgMax altitude h= (uSin )(2g)Using simulation of 3 different angles and use graphs to show that the maximum rangecan only be achieved at angle 45 degrees if u is a constant.Explain your solution in ii.i.ii.

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Initial velocity = u Angle of fire 0 Time of flight to apex of trajectory (uSiniyg Total time of flight t= (2usinoyg Range to apex of trajectory = (u*Sin20y2g Total range s- (usin20Mg Max altitude h= (uSin e)(2g) Using simulation of 3 different angles and use graphs to show that the maximum range can only be achieved at angle 45 degrees if u is a constant. i. ii. Explain your solution in ii.

Initial velocity = u Angle of fire 0 Time of flight to apex of trajectory (uSiniyg Total time of flight t= (2usinoyg Range to apex of trajectory = (u*Sin20y2g Total range s- (usin20Mg Max altitude h= (uSin e)(2g) Using simulation of 3 different angles and use graphs to show that the maximum range can only be achieved at angle 45 degrees if u is a constant. i. ii. Explain your solution in ii.

Classical Dynamics of Particles and Systems

5th Edition

ISBN:9780534408961

Author:Stephen T. Thornton, Jerry B. Marion

Publisher:Stephen T. Thornton, Jerry B. Marion

Chapter2: Newtonian Mechanics-single Particle

Section: Chapter Questions

Problem 2.36P

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