void countSort(int arr[], int n, int exp) { intoutput[n]; inti, count[10] = { 0 }; for (i=0; i=0; i--) { output[count[(arr[i] /exp) %10] -1] =arr[i]; count[(arr[i] /exp) %10]--; } for (i=0; i
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- import java.util.ArrayList;import java.util.Random; class Main { public static void main(String[] args) { Random rand = new Random(); ArrayList<Integer> a = new ArrayList<Integer>(); for(int i = 0; i < 100; i++) { a.add(rand.nextInt(100)); } print(a); System.out.println("----"); sort(a); print(a); // simplified Quicksort public static void sort(ArrayList<Integer> a) { if (a.size() <= 1) return; // Pick a Pivot int m = a.size() / 2; int pivot = a.get(m); } ArrayList<Integer> smaller = new Arraylist<Integer>(); ArrayList<Integer> same = new ArrayList<Integer>(); ArrayList<Integer> larger = new ArrayList<Integer>(); for (Integer x : a) { if (x < pivot) { smaller.add(x); } else if(x > pivot) { larger.add(x); } else { same.add(x); } } sort(smaller); sort(larger); a.clear(); a.addAll(smaller);…in Python Minima in permutations. Write a program that takes an integer n from the command line, generates a random permutation, prints the permutation, and prints the number of left-to-right minima in the permutation (the number of times an element is the smallest seen so far). Then write a program that takes integers m and n from the command line, generates m random permutations of length n, and prints the average number of left-to-right minima in the permutations generatedcreate a generic array stack and push/pop a million random ints using java.util.Random class. you also want to detect the time it takes to push and pop elements from the stack and you need to run the test multple times to see how the running time grows with increasing number of operations. use a outer loop that runs the program a million times (e.g. for(int i = 1; i<1000000; i+=1000000)).
- import java.util.Scanner;import java.util.ArrayList; public class UserIDSorting {// TODO: Write the partitioning algorithm - pick the middle element as the // pivot, compare the values using two index variables l and h (low and high), // initialized to the left and right sides of the current elements being sorted,// and determine if a swap is necessarypublic static int partition(ArrayList<String> userIDs, int i, int k) {} // TODO: Write the quicksort algorithm that recursively sorts the low and // high partitionspublic static void quicksort(ArrayList<String> userIDs, int i, int k) {} public static void main(String[] args) {Scanner scnr = new Scanner(System.in); ArrayList<String> userIDList = new ArrayList<String>(); String userID; userID = scnr.next();while (!userID.equals("-1")) {userIDList.add(userID);userID = scnr.next();}// Initial call to quicksort quicksort(userIDList, 0, userIDList.size() - 1); for (int i = 0; i < userIDList.size(); ++i)…import java.util.ArrayList; public class RemoveMin { public static void main(String[] args) { ArrayList<Integer> a = new ArrayList<Integer>(); // Add some integers to the array list a.add(14); a.add(29); a.add(19); a.add(3); a.add(15); a.add(62); a.add(18); a.add(97); a.add(44); a.add(31); a.add(51); a.add(78); // Print the array list - Note the use of the size() method and the get() method for (int i = 0; i < a.size(); i++) { System.out.print(a.get(i) + " "); } System.out.println(); //Remove the minimum element from ArrayList a removeMin(a); // Print the array list again for (int i = 0; i < a.size(); i++) { System.out.print(a.get(i) + " "); } System.out.println(); // Trick: You can also print the entire array by calling the toString() method…// MergeSortTest.java// Sorting an array with merge sort.import java.security.SecureRandom;import java.util.Arrays; public class MergeSortTest { // calls recursive sortArray method to begin merge sorting public static void mergeSort(int[] data) { sortArray(data, 0, data.length - 1); // sort entire array } // splits array, sorts subarrays and merges subarrays into sorted array private static void sortArray(int[] data, int low, int high) { // test base case; size of array equals 1 if ((high - low) >= 1) { // if not base case int middle1 = (low + high) / 2; // calculate middle of array int middle2 = middle1 + 1; // calculate next element over // split array in half; sort each half (recursive calls) sortArray(data, low, middle1); // first half of array sortArray(data, middle2, high); // second half of array // merge two sorted arrays after split calls…
- Java Bubble Sort but make it read the data 64, 34, 25, 12, 22, 11, 90 from a file not an array // Java program for implementation of Bubble Sort class BubbleSort { void bubbleSort(int arr[]) { int n = arr.length; for (int i = 0; i < n - 1; i++) for (int j = 0; j < n - i - 1; j++) if (arr[j] > arr[j + 1]) { // swap arr[j+1] and arr[j] int temp = arr[j]; arr[j] = arr[j + 1]; arr[j + 1] = temp; } } /* Prints the array */ void printArray(int arr[]) { int n = arr.length; for (int i = 0; i < n; ++i) System.out.print(arr[i] + " "); System.out.println(); } // Driver method to test above public static void main(String args[]) { BubbleSort ob = new BubbleSort(); int arr[] = { 64, 34, 25, 12, 22, 11, 90 }; // make it read from a file instead of having…Mergesort is a method that takes an integer array and returns a sorted copy of the same array. It first sorts the left half of the input array, then the right half of the input array, and finally merges the two sorted halves together into a sorted version of the input array. Implement the mergesort method public static int[] mergesort(int[] arr) { return new int[] {-1}; } *must be in this layout and done in javavoid radixSort(int arr[], int n) { intm=getMax(arr, n); for (intexp=1; m/exp>0; exp*=10) countSort(arr, n, exp); } void printData(int arr[], int start, int len) { if( start>=len ) return( 0 ); printf("%d\n", arr[start]); printData(arr, start+1, len); } int main() { intarr[]= {8, 9, 3, 4, 7, 2, 5, 6, 1}; intn=sizeof(arr) /sizeof(arr[0]); radixSort(arr, n); printData(arr, 0, n); return0; } In MIPS
- JAVA - Multi Dimensional Arrays Ask the user for the number of rows and columns of a two-dimensional array and then its integer elements. Print the row number of the row where the sum of all of its elements is even. For this problem, it is guaranteed that there is one and only one row of such case. Row count starts at 0. Input 1. One line containing an integer for the number of rows 2. One line containing an integer for the number of columns 3. Multiple lines containing at least one integer each line for the elements of the array Sample 2 7 4 1 1 2 0 5 0 Output Note that the row number starts at 0, not 1. Enter # of rows: 3 Enter # of columns: 3 Enter elements: 2 7 4 1 1 2 0 5 0 Even row: 1package sorting; import java.util.Arrays; import java.util.Random; import sorting.Heap; public class ComparisonSorter { public static void insertionSort(int[] arr) { for(int i=1;i<arr.length;i++) { int j = i-1; int toPlace = arr[i]; while(j>=0&&arr[j]>toPlace) { arr[j+1] = arr[j]; j--; } arr[j+1] = toPlace; } } public static void mergeSort(int [] arr) { mergeSortRecurse(arr,0,arr.length-1); } private static void mergeSortRecurse(int[] arr, int start, int end) { if(start>=end) return; int mid = start + ((end-start)/2); mergeSortRecurse(arr,start,mid); mergeSortRecurse(arr,mid+1,end); merge(arr,start,mid,end); } private static void merge(int[] arr, int start, int mid, int end) { int leftSize = mid - start +1; int rightSize = end - mid; int[] left = new int[leftSize+1]; int[] right = new int[rightSize+1]; int leftIndex; int rightIndex; for(leftIndex = 0; leftIndex<leftSize;leftIndex++) left[leftIndex] = arr[start+leftIndex]; for(rightIndex = 0;…package sorting; import java.util.Arrays; import java.util.Random; import sorting.Heap; public class ComparisonSorter { public static void insertionSort(int[] arr) { for(int i=1;i<arr.length;i++) { int j = i-1; int toPlace = arr[i]; while(j>=0&&arr[j]>toPlace) { arr[j+1] = arr[j]; j--; } arr[j+1] = toPlace; } } public static void mergeSort(int [] arr) { mergeSortRecurse(arr,0,arr.length-1); } private static void mergeSortRecurse(int[] arr, int start, int end) { if(start>=end) return; int mid = start + ((end-start)/2); mergeSortRecurse(arr,start,mid); mergeSortRecurse(arr,mid+1,end); merge(arr,start,mid,end); } private static void merge(int[] arr, int start, int mid, int end) { int leftSize = mid - start +1; int rightSize = end - mid; int[] left = new int[leftSize+1]; int[] right = new int[rightSize+1]; int leftIndex; int rightIndex; for(leftIndex = 0; leftIndex<leftSize;leftIndex++) left[leftIndex] = arr[start+leftIndex]; for(rightIndex = 0;…
