Iodine is sparingly soluble in pure water. However, it does dissolve' in solutions containing excess iodide ion because of the following reaction: (be) EI = (be)čI + (be).I K = 710. For each of the following cases calculate the equilibrium ratio of [I3] to [12]. 7.00x10-2 mol of I2 is added to 1.00 L of 7.00x10-1 M KI solution. Submit Answer Tries 0/5 The solution above is diluted to 13.00 L.

Chemistry & Chemical Reactivity
10th Edition
ISBN:9781337399074
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
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Chapter15: Principles Of Chemical Reactivity: Equilibria
Section15.6: Disturbing A Chemical Equilibrium
Problem 2.3ACP: A 0.64 g sample of the white crystalline dimer (4) is dissolved in 25.0 mL of benzene at 20 C. Use...
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Iodine is sparingly soluble in pure water. However, it does `dissolve' in solutions containing excess iodide ion because of the following reaction:
I(aq) + I2(aq) 13 (aq)
K = 710.
For each of the following cases calculate the equilibrium ratio of [I;] to [I2].
7.00x10-2 mol of I, is added to 1.00 L of 7.00x10-1 M KI solution.
Submit Answer Tries 0/5
The solution above is diluted to 13.00 L.
Transcribed Image Text:Iodine is sparingly soluble in pure water. However, it does `dissolve' in solutions containing excess iodide ion because of the following reaction: I(aq) + I2(aq) 13 (aq) K = 710. For each of the following cases calculate the equilibrium ratio of [I;] to [I2]. 7.00x10-2 mol of I, is added to 1.00 L of 7.00x10-1 M KI solution. Submit Answer Tries 0/5 The solution above is diluted to 13.00 L.
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