Ip Last edit was 2 minutes ago BIUA 1E E E - E E X 12 PE - KE - %3! ME - V= 3 h PE - KE = ME = 2 V= PE %3! KE - 1 m - ME m = 60 kg v = 8 m/s ME = KE + PE KE = (0.5)(m) (v)? PE = (m) (g)(h) %3D %3D 1) 2)

College Physics
10th Edition
ISBN:9781285737027
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter29: Nuclear Physics
Section: Chapter Questions
Problem 2P
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mass = 60 kg velocity= 8 m/s
ols Add-ons Help
Last edit was 2 minutes ago
A
三, 三三▼三▼三三X
Comic San.
12
BIU
田回▼
KE
1 m
ME =
m = 60 kg
v = 8 m/s
ME = KE + PE
KE = (0.5)(m) (v)²
PE = (m) (g)(h)
1)
3)
84
2)
Transcribed Image Text:ols Add-ons Help Last edit was 2 minutes ago A 三, 三三▼三▼三三X Comic San. 12 BIU 田回▼ KE 1 m ME = m = 60 kg v = 8 m/s ME = KE + PE KE = (0.5)(m) (v)² PE = (m) (g)(h) 1) 3) 84 2)
Physics O
elp
Last edit was 2 minutes ago
12
BIUA
1EE E
E E X
PE -
KE =
ME -
h =
PE =
KE =
ME =
PE =
KE -
1 m
ME =
m = 60 kg
v = 8 m/s
ME = KE + PE
KE = (0.5)(m) (v)²
PE = (m) (g)(h)
1)
2)
84%
Transcribed Image Text:Physics O elp Last edit was 2 minutes ago 12 BIUA 1EE E E E X PE - KE = ME - h = PE = KE = ME = PE = KE - 1 m ME = m = 60 kg v = 8 m/s ME = KE + PE KE = (0.5)(m) (v)² PE = (m) (g)(h) 1) 2) 84%
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