Iron is obtained from iron ore according to the following reaction: Fe2O3 + CO → Fe + CO2 (unbalanced) a. Assuming the blast furnace is 90.0 % efficient in recovering the iron, what is the actual mass of iron obtainable from a ton of ore? 1 ton = 2000.0 lb 1 lb = 453.6 g
7. Iron is obtained from iron ore according to the following reaction:
Fe2O3 + CO → Fe + CO2 (unbalanced)
a. Assuming the blast furnace is 90.0 % efficient in recovering the iron, what is the actual mass
of iron obtainable from a ton of ore? 1 ton = 2000.0 lb 1 lb = 453.6 g
Answer_____________
b. What is theoretical yield of iron if 200.0 g of Fe2O3 reacts with 100.0 g of CO?
Answer__________________
c.How many grams of excess reactant are left at the end of the reaction?
Answer__________________
The balanced reaction is given by-
Fe2O3 + 3 CO = 2 Fe + 3 CO2
(a) 1 tone of iron ore
1 tone = 2000 x 453.6 g = 907200 g
Molar mass of Fe2O3 =159.70 g/mol
So, 159.70 g of Fe2O3 =1 mol
1 g of Fe2O3 = (1 / 159.70) mol
907200 g of Fe2O3
= (907200 / 159.70) mol
= 5680.65 mol
Now,
Fe2O3 + 3 CO = 2 Fe + 3 CO2
In the above reaction equation,
1 mole of Fe2O3 (iron ore) produces 2 moles of Fe.
5680.65 mole of Fe2O3 (iron ore) produces (5680.65 x 2) moles of Fe.
5680.65 mole of Fe2O3 (iron ore) produces 11361.3 moles of Fe.
Now, molar mass of Fe = 55.85 g/mol
So, 1 mole of Fe = 55.85 g
11361.3 moles of Fe
= 11361.3 x 55.85 g = 634528.61 g
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