For question look at picture regarding precision % Is the precision of your two trials within 5 %? This means is your % average deviation<5 %. Support your answer with calculations.mu tue triglswas not Sample 1Sample 2Unknown CaCl2 solution code (if any)Unknown Code = _2%3D1.2.Volume of 0.100 M Na3PO4 solution used30 mL30ML3.Initial burette volume of CaCl2 solution0.6 m L20.64.Final burette volume of CaCl2 solution20.6 mL40.6 mL5.Volume of unknown CaCl2 solution used20 mL20 mL6.Mass of filter paperDo381 g0:356 q7.Mass of filter paper + Ca3(PO4)2 precipitate0.453 q0.3839.३६३8.Mass of Ca3(PO4)2 precipitate recoveredO.0720. 027 a9.Moles of Ca3(P04)2 recoveredO. 000232 mel0.0000 871 mol10.Moles of CaCl2 consumed in reaction0.000 696 mol0,000261molMolarity of unknown CaCl2 solution0.0348 M0.013111.12.Average Value for Molarity of Unknown CaCl2 solution0.024

Answered: Is the precision of your two trials…

Is the precision of your two trials within 5 %? This means is your % average deviation <5 %. Support your answer with calculations. nnt

Principles of Modern Chemistry

8th Edition

ISBN:9781305079113

Author:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler

Publisher:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler

Chapter11: Solutions

Section: Chapter Questions

Problem 10P

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Consider a 1.000-L stock solution of 9.69 M Na3PO4. A 2.000-mL aliquot is taken from this stock solution and diluted to a final volume of 1.000 L. A 5.000-mL aliquot is then taken from this new solution and further diluted to make a new solution with a final volume of 750.0 mL. Calculate Na+ in the final solution.
Stock iron(II) solution (200Ug mL-1 Fe) ferrous ammonium sulfate hexahydrate mass= 0.1437g, transfer it to a 100 ml beaker. add 15 ml approx of water and 15m1 'approx of dilute sulphuric acid (2M H2SO.). then transfer FeII to 100 ml flask makeup to the mark with water. calculate the moles of ferrous ammonium sulfate hexahydrate solution in unit ug/mL.
Show your complete solution and round-off your answers to four decimal places. A 0.1093-g sample of impure Na2CO3 was analyzed by the Volhard method. After adding 50.00 mL of 0.06911 N AgNO3, the sample was back titrated with 0.05781 N KSCN, requiring 27.36 mL to reach the end point. Calculate the % purity of the Na2CO3 sample. Answer = _% Na2CO3
using exactly 5.00 mL of 0.0400 M stock CuSO4 solution. Add 100 mL of water. Data for Part IMass of empty dish: 32.470 g empty dishVolume of 0.0400 M solution: 5.00 mL CuSO4 solution.Mass of dish and 0.0400 M solution: 37.497 g dish and solutionMass of dish and CuSO4 solid: 32.503 g dish and CuSO4 solidCalculations for Part I1. Calculate the mass of solution2. Calculate the mass of solid CuSO4 dissolved in the solution.3. Calculate the number of moles of solid CuSO4 dissolved in the solution.4. Calculate the mass of water evaporated from the solution.5. Calculate the density of solution, (g solution/mL solution).6. Calculate the % by mass, CuSO4 in solution (100 x g CuSO4/g solution).7. Calculate the molality of solution (moles CuSO4/kg solvent).8. Calculate the molarity of solution (moles CuSO4/L solution).9. Given that the true molarity is 0.0400 M, calculate the percent error of your result.
An unknown sample containing a mixture of NaCl and Na2CO3 was analyzed to determine the % composition of each compound. In the analysis for Na2CO3 (soda ash), the following data were obtained mass of unknown - 0.4436 g conc. of HCl used - 0.25 N initial volume - 0.5 mL final volume - 20.0 mL (MW soda ash) 106.12) 1.) What method was used to determine the concentration of HCl? 2.) What is the net volume of HCl used in the titration? 3.) What is % Na2CO3 in the given sample? NOTE: Round off your answer to a whole number (2 sig fig)
1.) Use the line of best ! Tables: Data Port 1. Synthesis of Asprin \table[[Mass of galicylic Acid used 2.024gt to calculate the concentration of the salicylic Acid in your asprin saple solution (in 50.0 ml volumettic flask) 2.) Use M1V1 = M2V2 to determine the concentration of salicylic acid in your 100.0 mL solution before dilutuon to 50.0mL for analysis. 3.) Determine the mass of salicylic acid present in the 4g sample of synthesized asprin tht was dissolved in the 100.0ml, volumetric flask 4.) Determine the percent of salicylic acid and percent asprin in the 4g sample of synthesized asprin7 5.) Calculate the theoretical yelld of asprin for your synthesis reaction. Assume that the salicylic acid used in the salicylic used in the synthesis reaction is the limiting reactant. 6. Determine the percent yild of the asprin for your synthesis. For the 1st cacization i got 1.340x10^-4 M C7H603 For the 2nd calculation i got M167x10^-5 Please check my calculations and explain the remaining
A solution of sulfuric acid was made by dissolving 20.0g of 98% sulfuric acid in a 250mL of water. (H2SO4 = 98.078 g/mol; H2O = 18.015 g/mol)Additional information for 35-37 What if the solution has a total volume of 262ml? 1. Express the concentration of this solution in % by weight.a. 7.3%b. 4.4%c. 8.0%d. 7.8% 2. Express the concentration in molaritya. 0.10 Mb. 2.00 Mc. 0.76 Md. 0.93 M 3. Express the concentration in normalitya. 2.0 Nb. 1.5 Nc. 1.0 Nd. 0.76 N 4. Express the concentration in molalitya. 0.80 mb. 0.77 mc. 1.00 md. 1.50 m
using exactly 5.00 mL of 0.0400 M stock CuSO4 solution. Add 100 mL of water. Data for Part IMass of empty dish: 32.470 g empty dishVolume of 0.0400 M solution: 5.00 mL CuSO4 solution.Mass of dish and 0.0400 M solution: 37.497 g dish and solutionMass of dish and CuSO4 solid: 32.503 g dish and CuSO4 solidCalculations for Part I1. Calculate the mass of solution? 5.027 g 2. Calculate the mass of solid CuSO4 dissolved in the solution? 0.033 g 3. Calculate the number of moles of solid CuSO4 dissolved in the solution? 2.07 x 10-4 mol4. Calculate the mass of water evaporated from the solution? 0.0414 M5. Calculate the density of solution, (g solution/mL solution)?6. Calculate the % by mass, CuSO4 in solution (100 x g CuSO4/g solution)?7. Calculate the molality of solution (moles CuSO4/kg solvent)?8. Calculate the molarity of solution (moles CuSO4/L solution)?9. Given that the true molarity is 0.0400 M, calculate the percent error…
A solution of HNO3HNO3 is standardized by reaction with pure sodium carbonate. 2H++Na2CO3⟶2Na++H2O+CO22H++Na2CO3⟶2Na++H2O+CO2 A volume of 24.78±0.06 mL24.78±0.06 mL of HNO3HNO3 solution was required for complete reaction with 0.8272±0.0007 g0.8272±0.0007 g of Na2CO3Na2CO3, (FM 105.988±0.001 g/mol105.988±0.001 g/mol). Find the molarity of the HNO3HNO3 solution and its absolute uncertainty.
Data of milk: (first trial) Mass of milk: 104.4579g Concentration of NaOH (M): 0.09639 Volume of NaOH solution used: 5.5 mL Data of milk: (2nd trial) Mass of milk: 103.8405g Concentration of NaOH (M): 0.09639 Volume of NaOH solution used: 5.3 mL
Part 1: A solution of sulfuric acid was made by dissolving 20.0g of 98% sulfuric acid in 250mL of water. (H2SO4 = 98.078 g/mol; H2O = 18.015 g/mol)Answer these items 1-4 for part 1:1. Express the concentration of this solution in % by weight. Additional information for items 2-3: What if the solution has a total volume of 262mL?2. Express the concentration in molarity3. Express the concentration in normality4. Express the concentration in molality Part 2: An alcohol, Ethanol (C2H5OH), is present in 1L of wine that is 12% alcohol by volume. The density of the solution is 0.984 g/mL, and the density of pure alcohol is 0.789 g/mL. (C2H5OH = 46.07 g/mol)Answer these items 1-2 for part 2:1. What is the weight of the alcohol present in wine?2. What is the molarity of the solution?
To prepare the solution you would place the solute in a 50.0 ml volumetric flask, and then fill to the mark with water while mixing. This would give a total solution volume of 50.0 ml. The 5.0 solution needs to be diluted to make 10.0 ml of a 2.0% solution. What volume of 5.0% solution should be used? Please answer fast i give you upvote.