Istandard hard water (containing 15gms of CaCO3 per 500 mL) required 25 mL of EDTA Solution for titration. 100 ml of water sample required 18 mL EDTA Solution, while same water after boiling required 12 mL EDTA solution. Calculate carbonate and non- carbonate hardness of water in ppm. Ans: Temporary hardness: 1440 ppm Permanent hardness: 2880 ppm Total hardness: 4320 ppm

Istandard hard water (containing 15gms of CaCO3 per 500 mL) required 25 mL of EDTA Solution for titration. 100 ml of water sample required 18 mL EDTA Solution, while same water after boiling required 12 mL EDTA solution. Calculate carbonate and non- carbonate hardness of water in ppm. Ans: Temporary hardness: 1440 ppm Permanent hardness: 2880 ppm Total hardness: 4320 ppm

Appl Of Ms Excel In Analytical Chemistry

2nd Edition

ISBN:9781285686691

Author:Crouch

Publisher:Crouch

Chapter10: Potentiometry And Redox Titrations

Section: Chapter Questions

Problem 8P

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10) 1.0 gram of CaCO3 was dissolved in HCl and the solution was made up to 1000 ml with distilled water. 50 ml of the solution required 45 ml of EDTA solution for titration, 50 ml of hard water sample required 28 ml of EDTA and after boiling and filtering required 15 ml of EDTA solution. Calculate Temporary Hardness. A. 288.6 ppmB. 166.6 ppmC. 88.6ppm 11) Calculate the Permanent Hardness for No. 10 A. 111 ppmB. 222 ppmC. 333 ppm 12) Calculate the Total Hardness for No. 10 A. 421.6 ppmB. 621.6 ppmC. 521.6 ppm
60 ml of standard hardness containing 1 mg of pure CaCO3 per ml consumed 22 ml of EDTA. 40 ml of water sample consumed 20 ml of EDTA solution using EBT indicator. 40 ml of water sample after boiling, filtering consumed 15 ml of EDTA. Calculate the temporary and permanent hardness of water sample.
A water sample is approximated to have a total hardness equal to 120.0ppm. How many milliliters of 0.01000N EDTA will be needed to titrate 250.00mL of the said water sample?(MM CaCO3=100.09g/mol). ** Need asap pls. Thanks.
A standard CaCO3 solution is prepared by dissolving 0.4193g in enough dilute HCl to effect solution and then diluted to 500ml solution. A 25.00ml aliquot requires 23.62ml EDTA solution for titration. A 25.00ml water sample determined for total hardness, requires 8.45ml of the EDTA solution using Eirochrome Black T indicator. Calculate the total hardness in the water sample expressed in ppm CaCO3.
. 100 ml boiled cooled and filtered water sample takes 9.6 ml of M/50 EDTA in titration. The Permanent hardness of the water sample in terms of ppm of CaCO3 equivalent is
A deepwell water sample of 100 mL was titrated with 0.010 M EDTA at pH 10 ( with Mg-EDTA pH 10 buffer reagent) and consumed 31 mL. Calculate the Total Hardness of the water sample as mg CaCO3. Ans in 3 sig figures. no need to write the unit.
Titration of 25.00ml of 0.100M I- with 0.0500M Ag+. Calculate pAg+ (=-log[Ag+]) at VAg+= 10.00ml; 49.50ml; 50.00ml; 50.50ml; 52.00ml. (Ksp,Ag+)= 8.3*10^-17
A 100 ml sample of water require 20 ml of 0.02 N EDTA for titration using EBT as indicator.100 ml of same water sample boiled and precipitate removed by filtration, the filtrate requires 9 ml of 0.02 N EDTA for titration. Calculate the total hardness, permanent hardness and temporary hardness of water sample.
Standardization of EDTA solution Trial number Volume of EDTA used (mL) 1 9.7 2 8.9 3 9.4 Calculate Average Molarity of EDTA and Relative Average Deviation (R.A.D.) Hardness Titration Trial number Volume of EDTA used (mL) 1 12.2 2 12.6 3 11.6 Average ppm CaCO3 and Relative Average Deviation (R.A.D.) I need. M(Ca2+)+V(Ca2+)->M(EDTA)+V(EDTA) 0,01M + 10ml -> ? + V(EDTA)
An automatic titration was performed with the following results: Standardized NaOH Solution Concentration: 0.1191 M Volume of HA- product examined in each trial: 25.00 mL Volume of Standardized NaOH Titrant used to achieve the first equivalence point: Trial #1: 1.300 mL Trial #2: 1.137 mL Trial #3: 1.140 mL Calculate the %(w/v) for each trial, Average Concetration (%), Deviation (%), Standard Deviation (%), and RSD (%)
A deep well sample of 100 mL was titrated with 0.010 M EDTA at pH=10 (with Mg-EDTA-pH 10 reagent) and consumed 30.15 mL using EBT indicator. Titration of another 100 mL of the same deep well sample with same titrant but the pH was adjusted to 12.10 and murrexide as indicator consumed 24.25 to reach end point. Calculate: a. Total hardness of water as CaCO3 b. ppm of Ca and Mg
A CaCO3 solution that will be used to standardize EDTA was prepared by dissolving 3.1251 g of solid CaCO3 in 100 mL dilute HCl. A 20.00 mL aliquot was taken for titration with EDTA consuming 32.00 mL of the titrant to reach the endpoint. Express the concentration of EDTA in molarity and in CaCO3 titer. MM Na2H2Y2•2H2O = 372.24 g/mole; MM CaCO3 = 100.09 g/mole