Data: t/°C 20 30 40 50 V NAOH / mL 13.1 26.2 16.0 21.8 *Volume of sample solution for titration: 25 mL, density of water/benzoic acid solution: 1.00 g/mL Calculations: I. Calculate the solubility, C, of benzoic acid in 100 g water: 20 °C: 30 °C: 40 °C: 50 °C: I. Calculation of InC and T -1 values. Inc

Data: t/°C 20 30 40 50 V NAOH / mL 13.1 26.2 16.0 21.8 *Volume of sample solution for titration: 25 mL, density of water/benzoic acid solution: 1.00 g/mL Calculations: I. Calculate the solubility, C, of benzoic acid in 100 g water: 20 °C: 30 °C: 40 °C: 50 °C: I. Calculation of InC and T -1 values. Inc

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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1.1The Ksp of Ca3 (PO4 ) 2 is 1.3 × 10−26 . Estimate the solubility of this salt in units of g. L −1 . You must show any reaction equation(s) that you may think are necessary. 1.2 If a sample of solid Ca3(PO4)2 is stirred into exactly one litre of a 0.550M solution of Na3PO4, how will the solubility of the salt compare with the answer that you have obtained in question 1.1? Explain you answer in a short sentence.
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In an experiment to calculate the solubility product (Ksp) of barium nitrate (Ba(NO3)2), an excess amount of Ba(NO3)2 was added to 2 liters of water at 25oC until the solution is saturated. Because Ba(NO3)2 is only slightly soluble in water, the excess Ba(NO3)2 was filtered out to get a solid-free mixture. The proponents of the experiment thought about using the concept of colligative properties, specifically boiling point elevation, to determine Ksp. It was observed in their experiments that the solution boils at 100.15 K. Barium nitrate dissociates via the process: ?a(??3)2(?) ⇄ ??2+(?q) + 2??-3(?q) ??p = [??2+][??3−]2 Calculate the following if Kb,water = 0.51 K-kg/mol: a) Amount of Ba(NO3)2 dissolved in grams. Molar mass of Ba(NO3)2 = 261.3 g/mol b) Solubility product, Ksp c) Vapor pressure of the solution in kPa
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