Item 10 10 of 15 A cross in Drosophila melanogaster involved the recessive X-linked genes for white eye (w), yellow body (y), and cut wings (c). A wild-type tri-hybrid female was crossed with wild-type male only the male offspring were tallied. On the basis of the results shown below, which of the choices shown best represents the genetic map of the three loci on the X-chromosome? Phenotype Male Offspring + y ct 63 w + + 60 w y ct 16 + + + 11 + + ct 4 w y + 2 + y + 247

Item 10 10 of 15 A cross in Drosophila melanogaster involved the recessive X-linked genes for white eye (w), yellow body (y), and cut wings (c). A wild-type tri-hybrid female was crossed with wild-type male only the male offspring were tallied. On the basis of the results shown below, which of the choices shown best represents the genetic map of the three loci on the X-chromosome? Phenotype Male Offspring + y ct 63 w + + 60 w y ct 16 + + + 11 + + ct 4 w y + 2 + y + 247

Biology: The Dynamic Science (MindTap Course List)

4th Edition

ISBN:9781305389892

Author:Peter J. Russell, Paul E. Hertz, Beverly McMillan

Publisher:Peter J. Russell, Paul E. Hertz, Beverly McMillan

Chapter13: Genes, Chromosomes, And Human Genetics

Section: Chapter Questions

Problem 8TYK: Another gene in Drosophila determines wing length. The dominant wild-type allele of this gene...

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In cats, the genotype AA produces tabby fur color; Aa is also a tabby, and aa is black. Another gene at a different locus is epistatic to the gene for fur color. When present in its dominant W form (WW or Ww), this gene blocks the formation of fur color and all the offspring are white; ww individuals develop normal fur color. What fur colors, and in what proportions, would you expect from the cross AaWw Aa Ww?
. A white-eyed female Drosophila is mated with a redeyed (wild-type) male, the reciprocal cross of the oneshown in Figure 15.4. What phenotypes and genotypesdo you predict for the offspring from this cross?
Male Drosophila expressing the autosomal recessivemutations sc (scute), ec (echinus), cv (crossveinless),and b (black) were crossed to phenotypically wildtype females, and the 3288 progeny listed wereobtained. (Only mutant traits are noted.)653 black, scute, echinus, crossveinless670 scute, echinus, crossveinless675 wild type655 black71 black, scute73 scute73 black, echinus, crossveinless74 echinus, crossveinless87 black, scute, echinus84 scute, echinus86 black, crossveinless83 crossveinless1 black, scute, crossveinless1 scute, crossveinless1 black, echinus1 echinusa. Diagram the genotype of the female parent.b. Map these loci.c. Do the data provide evidence of interference?Justify your answer with numbers.
Figure 5.1 presented abbreviated pedigrees looking at the inheritance of X-linked human conditions. El Figure 5.1a initiated with a male who was color blind and had hemophilia A. The grandsons and great-grandsons of this male were either color blind and had hemophilia A, or they had neither condition. a. Which if any individuals in the G Fig. 5.1a pedigree is a double heterozygote? b. Are any of the grandsons or great-grandsons shown in the pedigree the product of recombinant type gametes? c. Do the genes responsible for color blindness and hemophilia A segregate independently? d. If you examined many pedigrees, each starting with a man who was simultaneously color blind and had hemophilia A, do you think any grandsons or great-grandsons would ever have one condition but not the other? L Figure 5.1b initiated with a male who was color blind and had hemophilia B. The grandsons of this male were either only color blind, only had hemophilia B, had both conditions, or they had neither…
F1 female Drosophila heterozygous for cinnabar eye (cn), vestigial wings (vg) and roof wings (rf) genes were test crossed with males homozygous for all three traits. The following result were obtained. 382 cinnabar, vestigial 401 roof 3 cinnabar 4 roof, vestigial 59 cinnabar, roof, vestigial 67 wild 44 cinnabar, roof 40 vestigial The chromosomal interference is equal to? 0.24 0.32 0.42 0.58 0.49
Female Drosophila heterozygous for three recessive mutations e (ebony body), st (scarlet eyes), and ss (spineless bristles) were testcrossed, and the following progeny were obtained: Phenotype Number wild-type 67 ebony 8 ebony, scarlet 68 ebony, spineless 347 ebony, scarlet, spineless 78 scarlet 368 scarlet, spineless 10 spineless 54 (a) What indicates that the genes are linked? (b) What was the genotype of the original heterozygous females? (c) What is the order of the genes? (d) What is the map distance between e and st? (e) Between e and ss? (f) What is the coefficient of coincidence? (g) Diagram the crosses in this experiment.
In Drosophila, the sepia mutation (se, chromosome 3, position 26) results in dark brown eyes, while cinnabar (cn, chromosome 2, position 57.5) results in bright orange-red eyes. True breeding, wild type females are mated with true breeding males homozygous recessive for both traits. Using Drosophila notation, diagram the P1 and F1 crosses. P1 F1 Fill in the chart with phenotypic ratios that would be expected in the F2 generation. Use the space provided to show your work. Phenotype Females Males Overall (♀and ♂) =1 =1
A cross in Drosophila melanogaster involved the recessive X-linked genes for white eye (w), yellow body (y), and cut wings (c). A wild-type tri-hybrid female was crossed with wild-type males and only the male offspring were tallied. On the basis of the results shown below, which of the choices shown best represents the genetic map of the three loci on the X-chromosome? Phenotype Male Offspring + y ct 494 w + + 394 + + ct 28 w y + 35 + y + 105 w + ct 101 w y ct 5 + + + 3
Miniature wings (Xm) in Drosophila result from an X-linked allele that is recessive to the allele for long wings (X +). Give the genotypes of the parents in each of the following crosses. Male parent Female parent Male offspring Female offspring a. long long 231 long, 250 miniature 560 long 250 miniature b. miniature long 610 long 632 long c. miniature long 410 long, 417 miniature 412 long, 415 miniature 417 miniature 415 miniature d. long miniature 753 miniature 761 long e. long long 625 long 630 long
The recessive alleles k (kidney-shaped eyes instead ofwild-type round), c (cardinal-colored eyes instead of wildtype red), and e (ebony body instead of wild-type gray)identify three genes on chromosome 3 of Drosophila.Females with kidney-shaped, cardinal-colored eyes weremated with ebony males. The F1 was wild type. When F1females were testcrossed with kk cc ee males, the following progeny phenotypes were obtained:k c e 3k c + 876k + e 67k + + 49+ c e 44+ c + 58+ + e 899+ + + 4Total 2000a. Determine the order of the genes and the mapdistances between them.b. Draw the chromosomes of the parents and the F1.c. Calculate interference and say what you think of itssignificance
In Drosophila, a cross was made between females expressing thethree X-linked recessive traits, scute bristles (sc), sable body (s),and vermilion eyes (v), and wild-type males. All females were wildtype in the F1, while all males expressed all three mutant traits.The cross was carried to the F2 generation and 1000 offspringwere counted, with the results shown in the following table. Nodetermination of sex was made in the F2 data. Question:Calculate the coefficient of coincidence; does this represent positive or negative interference? Phenotype Offspringsc s v 314+ + + 280+ s v 150sc + + 156sc + v 46+ s + 30sc s + 10+ + v 14
In Drosophila, the dominant Bar mutation (B, chromosome X, position 57) results in thin bar- shaped eyes, while the recessive singed (sn, chromosome X, position 21) results burnt looking bristles. True breeding, wild type females are mated with true breeding males with Bar eyes and singed bristles. Using Drosophila notation, diagram the P1 and F1 crosses. P1 F1 Fill in the chart with phenotypic ratios that would be expected in the F2 generation. Use the space provided to show your work. Phenotype Females Males Overall (♀and ♂) =1 =1 =1