Question
Asked Oct 3, 2019

What is the normal force at point A and the reaction at point B given thr static friction of 0.85?

IU
www. u
2/NTERNAL
HIN GE
AN
7.5m
3m
A
NS
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IU www. u 2/NTERNAL HIN GE AN 7.5m 3m A NS

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Expert Answer

Step 1

Given information

AB 10 m, BC =7.5m
=0.85
force along AB is 5 kN
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AB 10 m, BC =7.5m =0.85 force along AB is 5 kN

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Step 2

Free body diagram is given below, using Pythagoras theorem AF is calculated as

AF =AB2- BF2
AF = 10-32
AF 9.53m
RB
B
5 N
10 m
3 m
5 Cos8
A
f
P
N
co
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AF =AB2- BF2 AF = 10-32 AF 9.53m RB B 5 N 10 m 3 m 5 Cos8 A f P N co

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Step 3

Balancing forces in ver...

Σ-
N 5sine
= 0
N 5x
10
N 1.5kN
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Σ- N 5sine = 0 N 5x 10 N 1.5kN

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