I’ve done this question but I think I’ve done it wrong. Calculate how much 95% Ethel alcohol will be prepared to dissolve 0.3g of sulfanilamide at 78 degrees using the table (pictured below from my textbook) and, based on that volume, calculate how much sulfanilamide will remain dissolved in the mother liquor after the mixture is cooled to 0 degrees. For the volume at 78 I got 1.47mL and for the difference once it cooled to 0 degrees I got 19.96 mL. If I got these wrong could you point me in the right direction as how to solve this? Thank you!

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Asked Sep 16, 2019
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I’ve done this question but I think I’ve done it wrong. Calculate how much 95% Ethel alcohol will be prepared to dissolve 0.3g of sulfanilamide at 78 degrees using the table (pictured below from my textbook) and, based on that volume, calculate how much sulfanilamide will remain dissolved in the mother liquor after the mixture is cooled to 0 degrees. For the volume at 78 I got 1.47mL and for the difference once it cooled to 0 degrees I got 19.96 mL. If I got these wrong could you point me in the right direction as how to solve this? Thank you! 

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Expert Answer

Step 1

The relationship between milligrams (mg) and grams (g) is written below.

1 g = 1000 mg

Step 2

The solubility of sulfanilamide in 95% ethanol is 210 mg/mL. Now, convert 210 mg/mL into g/mL using the above relation.

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210 mg/mL 210 mg/mLx 1000 mg 0.210 g/mL

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Step 3

The mass 0.210 g of sulfanilamide is dissolved in 1 mL of ethyl alcohol, the volume of et...

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1 mL -x0.3g 0.210 g/mL V ethylaleohol =1.4 mL

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