iving the mole to mole ratio for converting from moles of nickel (II) nitrate hexahydrate to moles of nickel (II) phosphate. What is it? a. 1 mol Ni3(PO4)2 / 3 mol Ni(NO3)2•6H2O b. 1 mol Ni(NO3)2 / 1 mol Ni3(PO4)2 c. 1 mol Ni(NO3)2•6H2O / 1 mol Ni3(PO4)2 d. None of these e. 1 mol Ni3(PO4)2 / 1 mol Ni(NO3)2•6H2O f. 1 mol Ni3(PO4)2 / 3 mol Ni(NO3)2 g. 3 mol Ni(NO3)2•6H2O / 1 mol Ni3(PO4)2 h. 1 mol Ni(NO3)2•6H2O / 3 mol Ni3(PO4)2 If all of the nickel (II) nitrate hexahydrate (5.226 g) react how many grams of Ni3(PO4)2 will form? a. 0.3379 g b. 2.192 g c. 0.4575 g d. 2.650 g e. None of these f. 6.577 g g. 13.25 g h. 7.492 g i. 0.9150 g j. 1.325 g k. 3.746 g
iving the mole to mole ratio for converting from moles of nickel (II) nitrate hexahydrate to moles of nickel (II) phosphate. What is it? a. 1 mol Ni3(PO4)2 / 3 mol Ni(NO3)2•6H2O b. 1 mol Ni(NO3)2 / 1 mol Ni3(PO4)2 c. 1 mol Ni(NO3)2•6H2O / 1 mol Ni3(PO4)2 d. None of these e. 1 mol Ni3(PO4)2 / 1 mol Ni(NO3)2•6H2O f. 1 mol Ni3(PO4)2 / 3 mol Ni(NO3)2 g. 3 mol Ni(NO3)2•6H2O / 1 mol Ni3(PO4)2 h. 1 mol Ni(NO3)2•6H2O / 3 mol Ni3(PO4)2 If all of the nickel (II) nitrate hexahydrate (5.226 g) react how many grams of Ni3(PO4)2 will form? a. 0.3379 g b. 2.192 g c. 0.4575 g d. 2.650 g e. None of these f. 6.577 g g. 13.25 g h. 7.492 g i. 0.9150 g j. 1.325 g k. 3.746 g
Chemistry: An Atoms First Approach
2nd Edition
ISBN:9781305079243
Author:Steven S. Zumdahl, Susan A. Zumdahl
Publisher:Steven S. Zumdahl, Susan A. Zumdahl
Chapter7: Chemical Energy
Section: Chapter Questions
Problem 134IP: On Easter Sunday, April 3, 1983, nitric acid spilled from a tank car near downtown Denver, Colorado....
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3 Ni(NO3)2•6H2O (s) + 2 Na3PO4 (aq) --> Ni3(PO4)2 (s) + 6 NaNO3 (aq)
if 5.226 g Ni(NO3)2•6H2O is allowed to react with 25.00 ml of 0.1000 M Na3PO4 . How many grams of Ni3(PO4)2 can form? Start by giving the mole to mole ratio for converting from moles of nickel (II) nitrate hexahydrate to moles of nickel (II) phosphate. What is it?
a. 1 mol Ni3(PO4)2 / 3 mol Ni(NO3)2•6H2O
b. 1 mol Ni(NO3)2 / 1 mol Ni3(PO4)2
c. 1 mol Ni(NO3)2•6H2O / 1 mol Ni3(PO4)2
d. None of these
e. 1 mol Ni3(PO4)2 / 1 mol Ni(NO3)2•6H2O
f. 1 mol Ni3(PO4)2 / 3 mol Ni(NO3)2
g. 3 mol Ni(NO3)2•6H2O / 1 mol Ni3(PO4)2
h. 1 mol Ni(NO3)2•6H2O / 3 mol Ni3(PO4)2
If all of the nickel (II) nitrate hexahydrate (5.226 g) react how many grams of Ni3(PO4)2 will form?
a. 0.3379 g
b. 2.192 g
c. 0.4575 g
d. 2.650 g
e. None of these
f. 6.577 g
g. 13.25 g
h. 7.492 g
i. 0.9150 g
j. 1.325 g
k. 3.746 g
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