note: SN = 18, to the topload will be 118kN 5.0 m5.50 m6.0 m7.0 m5.0 m(1b0+SN) KN >B144 kN120 KN96 KNMIN5.0 m4.50 m4.20 mI 4.0 m 2. Cantilever Method: The frame shown is subjected to lateral loads as shown. Supports S, T, U V, W andX are rigid supports. Column HMS (400mm x 400 mm)Column ADINT (500 mm x 600 mm)Column BEJOU (600 mm x 600 mm)Column CFKPV (500 mm x 600 mm)Column GLQW (500 mm x 500 mm)Column RX (300mm x 300 mm)Determine the followinad) Summarize your results by drawing the frame with the internal forces.

data we have X = a1x1 +a2x2+a3x3+a4x4+a5x5+a6x6 Therefore, X = 12.78 X1=12.78m , X2 =7.78m X3…

Answered: K 4.50 m 4.20 m

Engineering

Civil Engineering

K 4.50 m 4.20 m

Steel Design (Activate Learning with these NEW titles from Engineering!)

6th Edition

ISBN:9781337094740

Author:Segui, William T.

Publisher:Segui, William T.

Chapter5: Beams

Section: Chapter Questions

Problem 5.5.11P

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Question

note: SN = 18, to the topload will be 118kN

5.0 m
5.50 m
6.0 m
7.0 m
5.0 m
(1b0+SN) KN >
B
144 kN
120 KN
96 KN
M
IN
5.0 m
4.50 m
4.20 m
I 4.0 m

2. Cantilever Method: The frame shown is subjected to lateral loads as shown. Supports S, T, U V, W and
X are rigid supports. Column HMS (400mm x 400 mm)
Column ADINT (500 mm x 600 mm)
Column BEJOU (600 mm x 600 mm)
Column CFKPV (500 mm x 600 mm)
Column GLQW (500 mm x 500 mm)
Column RX (300mm x 300 mm)
Determine the followina
d) Summarize your results by drawing the frame with the internal forces.

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