k m A block of mass m = 5.20 kg is being suspended at rest by an extended spring of spring constant k = 36.0 N/m and an external force F = 20.0 N downward. The spring is attached to the ceiling and has an extended length of s = 2.45 m. What is the relaxed length so of the spring?

Q: A 2.50 kg mass is pushed against a horizontal spring of force constant 25.0 N/cm on a table with a…

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Q: |When a 2.50-kg object is hung vertically on a cer- tain light spring described by Hooke's law, the…

A: Given data:  Mass of object (m) = 2.50 kg Spring Stretched by distance (x) = 2.76 cm

Q: When a 2.40-kg object is hung vertically on a certain light spring described by Hooke's law, the…

A: Given: The mass of the object is 2.4 kg. The spring constant is 2.58 cm.

Q: A spring-loaded pellet gun is designed to fire 2.50 g projectiles horizontally at a speed of 45.2…

A: (a) The spring energy is E1=12kx2 Kinetic energy of pallet is E2=12mv2 According to conservation of…

Q: A 2.00-kg package is released on a 53.1° incline, 4.00 m from a long spring with force constant 1.20…

A: Given a  2.00 kg package is released on a 53.1◦ incline, 4.00 m from a long spring with force…

Q: When a 2.50-kg object is hung vertically on a cer- tain light spring described by Hooke's law, the…

A:

Q: (a) Find the magnitude of the force required to compress the spring by 4.10 cm from its unstretched…

A: a) The spring force required to compressed by 4.10(x) cm from unstetched length, F= kx, where k=129…

Q: Q2) A block of mass m= 1.09 kg is pushed against an ideal, massless spring with spring constant k=…

A: m=1.09 kg k=10.5 N/m x1=-1.96 m let the speed at equilibrium be v

Q: All questions please.

A:

Q: A 1.60-kg object is held 1.30 m above a relaxed, massless vertical spring with a force constant of…

A: Solution: Given that m = 1.6 kg h = 1.3 m k = 315 N/m

Q: A 1.60-kg object is held 1.40 m above a relaxed, massless vertical spring with a force constant of…

A: mass of object (m) = 1.60 kg height of object above spring (h) = 1.40 m force constant (k) = 300 Nm…

Q: A spring-loaded pellet gun is designed to fire 2.50 g projectiles horizontally at a speed of 42.2…

A: Given data The mass is m=2.50 g The speed is v=42.2 m/s The spring difference is x=7.10 cm (a) The…

Q: the motion of the block, what is its maximum speed? Express your answer to three significant figures…

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Q: When a 2.50-kg object is hung vertically on a certain light spring described by Hooke’s law, the…

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Q: 5. ssm A person who weighs 670 N steps onto a spring scale in the bathroom, and the spring…

A: 5. The value of spring constant can be calculated from force applied to the spring and the…

Q: When a 2.20-kg object is hung vertically on a certain light spring described by Hooke's law, the…

A:

Q: A toy gun uses a spring with a force constant of 300 N/m to propel a 10.0-g steel ball. If the…

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Q: T M k A block of mass m = 23.0 kg is at rest on a frictionless inclined plane with angle 0 = 40.0°.…

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Q: A 0.300-kg block along a horizontal track has a speed of 1.30 m/s immediately before colliding with…

A: a)Change in kinetic energy of block is the equal to the potential energy of compressed spring.

Q: A 2.0kg mass is placed against a spring of force constant 800.0N/m, which has been compressed 0.22m.…

A: Given Data: The mass of the object is: m=2.0 kg The force constant of the spring is: k=800.0 N/m The…

Q: Fish are hung on a spring scale to determine their mass (most fishermen feel no obligation to report…

A:

Q: One type of BB gun uses a spring-driven plunger to blow the BB from its barrel. (a) Calculate the…

A: Compression x = 0.140 m Mass m = 0.0560 kg Speed v = 18 m/s

Q: A 2.00 kg package is released on a 53.1° incline, 4.00 m from a long spring with force constant 1.20…

A: Given that, m=2 kg, θ=53.10, l=4 meter ,k=120N/m, μs=0.40, μk=0.20 a) Work done by non-conservative…

Q: When a 2.10-kg object is hung vertically on a certain light spring described by Hooke's law, the…

A: (a)The force on the spring is,F=mg                                               m=2.10kg,g=9.8…

Q: A 15.0 kg crate is supported by a spring 1.) attached to the ceiling and a cable attached to the…

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Q: A 1.20-kg object is held 1.05 m above a relaxed, massless vertical spring with a force constant of…

A:

Q: A 0.250-kg block along a horizontal track has a speed of 1.50m/s immediately before colliding with a…

A:

Q: A block of mass 0.250 kg is placed on top of a light, vertical spring of force constant 5000 N/m and…

A:

Q: A 1.20-kg object is held 1.30 m above a relaxed, massless vertical spring with a force constant of…

A:

Q: A 0.200-kg block along a horizontal track has a speed of 1.60 m/s immediately before colliding with…

A: The mass of the block, m = 0.200 kg. The speed of the block, v = 1.60 m/s. The force constant of the…

Q: When a 2.80-kg object is hung vertically on a certain light spring described by Hooke's law, the…

A: The mass of the object is m = 2.80 kg. The stretch in the spring is x = 2.68 cm = 0.0268 m. Assume…

Q: A 1.60-kg object is held 1.00 m above a relaxed, massless vertical spring with a force constant of…

A: Mass of object, m=1.6kg Height of object above the spring, h=1m Spring constant, k=300N/m

Q: A 10 kg block on a horizontal frictionless surface is tied to a light spring of constant (0.80 kN /…

A: Given that,  The mass (m) of the block is 10 kg. The spring constant (k) of the spring is 0.80 kN/m…

Q: When a 2.90-kg object is hung vertically on a certain light spring described by Hooke's law, the…

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Q: Part A During the motion of the block, what is its maximum speed? Express your answer to three…

A: Given  Mass of block m=0.4kg Spring constant k=200N/m  speed at x=0.160m is v=3m/s

Q: Problem B) A mass of 4 kg on a horizontal surface has an initial velocity of 5 m/s when it hits a…

A: “Since you have asked multiple question, we will solve the first question for you. If you want any…

Q: A 1.60-kg object is held 1.30 m above a relaxed, massless vertical spring with a force constant of…

A: A 1.60-kg object is held 1.30 m above a relaxed, massless vertical spring with a force constant of…

Q: When a 2.10-kg object is hung vertically on a certain light spring described by Hooke's law, the…

A: Given mass of object m = 2.10 kg stretch in spring y = 2.98 cm = 0.0298 m We have to find our spring…

Q: The springs of a pickup truck act like a single spring with a force constant of k = 1.25 × 105 N/m.…

A: a)the magnitude of  restoring force is equal to the weight of the load

Q: A 1.40-kg object is held 1.00 m above a relaxed, massless vertical spring with a force constant of…

A: Given  Initial height of mass is 1m Final height is -X m Where X is the compression in spring. K =…

Q: A spring has a length of 0.270 m when a 0.300 kg mass hangs from it, and a length of 0.750 m when a…

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Q: A spring has a length of 0.280 m when a 0.300 kg mass hangs from it, and a length of 0.750 m when a…

A: m1 = 2.70 kg m2 = 0.300 kg l1 = -0.750 m l2 = -0.280 m We know g = 9.8 m/s²    Where l1 and l2 are…

Q: A mass of 70.0 g is hung on the end of a string that is 2.00 m in length. It is given an initial…

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Q: A 1.60-kg object is held 1.15 m above a relaxed, massless vertical spring with a force constant of…

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Q: (a) Determine the force constant (in N/m) of the spring, if the box compresses the spring 7.5 cm…

A: The acceleration of box is calculated by use of kinematics formula,  v2=u2+2as The final velocity v…

Spring Potential Energy

The potential energy is the energy possessed by a body by virtue of its position or the energy held by the object due to its position relative to other objects, its force like stresses, charge, and other factors affecting the particles of the body. The potential energy is the measure of the net work done by or on the body. The spring potential energy is the potential energy stored due to the deformation of an elastic spring and this elasticity is due to the stretched spring. The elasticity is the ability of a solid-state matter to come back to its equilibrium position or original position after any kind of external force is acted on it. It is also known as Elastic potential energy. The potential energy here is caused due to the displacement of the spring from its equilibrium position to another position and this potential energy is equal to the net work done due to the stretching of the spring. It also resembles the same mechanics of the oscillation of a simple pendulum, where due to the external force, the object moves from its equilibrium position to its maximum ends and the periodic motion continues till it comes back to the equilibrium position to rest.