T M k A block of mass m = 23.0 kg is at rest on a frictionless inclined plane with angle 0 = 40.0°. It is also attached to a compressed spring with spring constant k = 58.4 N/m on the lower end of the inclined plane and with a taut rope with tension T = 45.0 N at the other end. If the compressed length of the spring is s = 4.85 m, what is the relaxed length of the spring so? TIT.

Q: A spring is extended by 50 mm with the application of a force of 10N, and the spring constant is…

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Q: When a block is suspended from a vertically hanging spring, it stretches the spring from its…

A: Given : Total length, xf = 5.50 cm = 0.055 m Original length, xi = 4.50 cm = 0.045 m On horizontal…

Q: A spring with spring constant 94 N/m and rest length 27.2 cm is used to pull a wooden block of…

A: GIven data The spring constant is given as k = 94 N/m. The rest length is given as l = 27.2 cm. The…

Q: (b) An clastic string AB of natural length 2 m has the end A fixed. A load of mass 4kg is attached…

A: →Let AB be the string  of length 2 m with mass 4 kg attached  at B which is     rotating at a speed…

Q: A 2 kg block is released from rest at position 1, slides down a frictionless curve, proceeds on a…

A: As energy cannot be created or destroyed, it can only be transferred from one form to another.…

Q: A spring-loaded pellet gun is designed to fire 2.50 g projectiles horizontally at a speed of 45.2…

A: (a) The spring energy is E1=12kx2 Kinetic energy of pallet is E2=12mv2 According to conservation of…

Q: A 2.00-kg package is released on a 53.1° incline, 4.00 m from a long spring with force constant 1.20…

A: Given a  2.00 kg package is released on a 53.1◦ incline, 4.00 m from a long spring with force…

Q: A spring with a spring constant of 335 N/m is initially compressed by a distance of 0.045 m from its…

A: Given data: k = 335 N/m x= 0.045 m m=0.045 kg Need to determine the speed of the block.

Q: A 34 kg child uses a pogo stick to bounce up and down. The spring constant, k, of the toy equals…

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Q: If possible, express your final answer in the form u(1) = Rcos(@,t – 8). 4. A 10-kg mass is attached…

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Q: A block of mass m = 0.32 kg is set against a spring with a spring constant of k1 = 681 N/m which has…

A: Using the conservation of energy, 12k1d12-μkmgx=12k2d22

Q: Consider a 4.34 kg block that is dragged by a spring on a (relatively) frictionless horizontal…

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Q: A spring-loaded pellet gun is designed to fire 2.50 g projectiles horizontally at a speed of 42.2…

A: Given data The mass is m=2.50 g The speed is v=42.2 m/s The spring difference is x=7.10 cm (a) The…

Q: A horizontal spring (with a spring constant of 1000 N/m) is compressed by some amount, A, by a mass…

A: GIVEN: Force constant of spring = 1000N/m mass = 3kg velocity of mass = 15m/s

Q: A weight of mass m is at rest at O when suspended from a spring, as shown. When it is pulled down…

A: The rate of change of gravitational potential energy is  smallest at A, therefore statements 1, 2…

Q: Question 1 k=163 N/m m=0.2kg d A A mass of m=0.2kg moves on a horizontal surface. The coefficient of…

A: Givenm =0.2 kgμk =0.1 Initial velocity =v0 =3.21 m/sFinal velocity = v' = 0.9 v0K =163 N/m

Q: 1.5Hz, 0.67sec. B. 0.67HZ, 1.5 sec. C. 0.0012HZ, 864sec. D. 864 H2, U.0012sec. 4. A block of mass…

A: According to guideline we can solve only first question. A block of mass 1.6kg is attached to a…

Q: k m A block of mass m = 5.20 kg is being suspended at rest by an extended spring of spring constant…

A: M = 5.2kg  K= 36 N/m  F= 20N  s= 2.45m

Q: A gymnast of mass 52.0 kg is jumping on a trampoline. She jumps so that her feet reach a maximum…

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Q: Hooke's law describes a certain light spring of unstretched length 34.2 cm. When one end is attached…

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Q: A 2.00 kg package is released on a 53.1° incline, 4.00 m from a long spring with force constant 1.20…

A: Given that, m=2 kg, θ=53.10, l=4 meter ,k=120N/m, μs=0.40, μk=0.20 a) Work done by non-conservative…

Q: A spring with a spring constant of 303 N/m is initially compressed by a distance of 0.056 m from its…

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Q: A block of mass 2.0 kg is attached to a horizontal spring that has a force constant of 100.0 N/m .…

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Q: Consider an object of mass 0.150kg that is attached to a horizontal spring of spring constant 35.2…

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Q: ( ANSWER e,f, and g ), a is given ) You have two equal masses m1 and m2 and a spring with a…

A: Given: The mass m1 = m2 = 0.500 kg. The spring constant k = 290 N/m. You now pull the mass m2 down a…

Q: I just need the last part of the question

A: According to work energy theorem, change in kinetic energy is equal to work done by spring and…

Q: tion between the block and the plane is μk = 0.13. In the initial position, where the spring is…

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Q: A simple pendulum is suspended from the ceiling by means of a string and has a length of 1.56 m…

A: Given Data:- Length of the pendulum is l=1.56 m Initial speed of the pendulum is v0=1.73 m/s…

Q: When a 2.90-kg object is hung vertically on a certain light spring described by Hooke's law, the…

A:

Q: A brick of mass m = 0.48 kg is set against a spring with a spring constant of k1 = 619 N/m which has…

A: Given: m =0.48 kgk1=619 N/md1=0.1mk2=244 N/mμk=0.5x=1md2=?

Q: A spring with a spring constant of k = 192 N/m is initially compressed by a block a distance d =…

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Q: n ideal spring hangs from the ceiling. A 1.65 kg1.65 kg mass is hung from the spring, stretching the…

A: Given that           The mass of the hung (m) = 1.65Kg         stretching the spring a distance(x) =…

Q: A 2.85 kgkg block on a horizontal floor is attached to a horizontal spring that is initially…

A: Apply Newton’s second law at the vertical motion of the block, then n-mg=0n=mg=2.85 kg9.8 m/s2=27.93…

Q: One end of a horizontal spring with force constant 130.0 N/mN/m is attached to a vertical wall. A…

A: The block's mass is, m=5 kg The spring constant is, k=130 N/m The magnitude of the force is, F=89 N…

Q: 14) A block of mass 0.20 kg is against a spring compressed 0.20 m with spring constant 70 N/m. When…

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Q: Consider a pendulum of mass “m" attached to a spring of mass "M' that is free to move in single…

A: We know that the formula of the spring force is given as  F = -kx  here k is the spring constant  x…

Q: A spring with a spring constant of 383 N/m is initially compressed by a distance of 0.076 m from its…

A: The elastic potential energy stored in a compressed spring is given by UE = 12kx2, where k = spring…

Q: k=325 N/m 3 kg A 50 cm A 3 kg object is attached to a spring in a frictional horizontal plane and…

A: Given data: The mass of object is m=3 kg. The compression in spring is x=50 cm=0.5 m. The spring…

Q: A spring with a mass of 2 kg has natural length 0.5 m. A force of 25.6 N is required to maintain it…

A: Mass of the spring=2 kg Natural length =0.5 m Stretched length=0.7 m Force=25.6 N

Q: A spring has a length of 0.180 m when a 0.300 kg mass hangs from it, and a length of 0.750 m when a…

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Q: A 2.50-kg block on a horizontal floor is pushed against a horizontal spring that is initially…

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Q: A spring with a spring constant of 247 N/m is initially compressed by a distance of O.044 m from its…

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Q: A package of mass mmm = 6.00 kgkg is released on a 53.1∘∘ incline, a distance DDD = 4.00 mm from a…

A: Solution: Given that package of mass m = 6.00 kg θ = 53.1 ° D = 4m  spring with force constant k =…

Spring Potential Energy

The potential energy is the energy possessed by a body by virtue of its position or the energy held by the object due to its position relative to other objects, its force like stresses, charge, and other factors affecting the particles of the body. The potential energy is the measure of the net work done by or on the body. The spring potential energy is the potential energy stored due to the deformation of an elastic spring and this elasticity is due to the stretched spring. The elasticity is the ability of a solid-state matter to come back to its equilibrium position or original position after any kind of external force is acted on it. It is also known as Elastic potential energy. The potential energy here is caused due to the displacement of the spring from its equilibrium position to another position and this potential energy is equal to the net work done due to the stretching of the spring. It also resembles the same mechanics of the oscillation of a simple pendulum, where due to the external force, the object moves from its equilibrium position to its maximum ends and the periodic motion continues till it comes back to the equilibrium position to rest.