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Q: 20.0° has a spring of force constant k = 480 N/m fastened securely at the bottom so that the spring…

A: Let m be the mass of the block, d be the distance between the uncompressed spring and block, v be…

Q: An object is attached to a horizontal spring and somewhere along its motion has a kinetic and…

A: Total mechanical energy of the system is sum of kinetic energy and potential energy. T.E = K.E…

Q: h one end of a spring with a force constant k = 753 N/m to a wall and the other end to a mass  m =…

A: Givenk=753 N/mm=1.42 kgxi=6.56 cm=0.0656 m

Q: An m=20.0g object is held against the free end of a spring of constant k=25.0N/m that is compressed…

A: The time period of the object fall from the 1 m off the table Substitute all values in the above…

Q: A block of mass m = 2.00 kg is attached to a spring of force constant k = 515 N/m as shown in the…

A: Solutions is given by

Q: As shown in the figure, a 1.5 kg box is held at rest against a spring with a force constant k = 795…

A: Given data: Mass of the box, m=1.5 kg Force constant, k=795 N/m Coefficient of kinetic friction,…

Q: A block of mass m = 2.00 kg is attached to a spring of force constant k = 450 N/m as shown in the…

A: Let the speed of the block as it passes through the equilibrium point be denoted as vTotal energy of…

Q: A scene in a movie has a stuntman falling through a floor onto a bed in the room below. The plan is…

A: Spring constant (k)= 65144 Nm Compression (d) = 14.65 cm Height of mass above the spring (h) = 4.12…

Q: As shown in the figure below, a box of mass m = 8.00 kg is sliding across a horizontal frictionless…

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Q: An m = 20.0 g object is held against the free end of a spring d, of constant k = 25.0 N/m that is…

A:

Q: Sketch a pictureand show the calculation (including the starting formula) for the total energy in a…

A: In triangle ABC , AC = L = length of the string = hypotenuseAB = adjacent AD = length of string = L…

Q: simple pendulum is suspended from the ceiling by means of a string and the pendulum has a length of…

A:

Q: A horizontal spring attached to a wall has a force constant of k = 860 N/m. A block of mass m = 2.00…

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Q: A block of mass m= 0.28 kg is resting against the spring with force constant K= 250 N/m and…

A: Given: The mass of the object is 0.28 kg. The spring constant is 250 N/m. The compression in the…

Q: A block of mass m = 2.00 kg is attached to a spring of force constant k = 525 N/m as shown in the…

A: Solution

Q: A 0.20-kg mass is hung from a vertical spring of force constant 55 N/m. When the spring is released…

A:

Q: A block of mass (m=2.00kg) is attached to a spring of force constant k=4.05x10^2 N/m that lies on a…

A:

Q: A block of mass m = 2.00 kg is attached to a spring of force constant k = 545 N/m as shown in the…

A: Mass of block M = 2.00 kg  Spring constant k = 545 N/m  Displacement x = 4.45 cm = 0.0445 m We need…

Q: A block of mass m = 2.00 kg is attached to a spring of force constant k = 590 N/m as shown in the…

A: Given values m = 2 kg, X = 4.05 cm = 4.05 x 10-2 m Spring constant, k=590 N/m

Q: A block of mass m = 2.00 kg is attached to a spring of force constant k = 4.75 ✕ 102 N/m that lies…

A:

Q: An air glider of mass m = 0.500 kg is on a level air track and connected to a massless ideal spring…

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Q: A spring of negligible mass stretches 3.46 cm from its relaxed length when a force of 5.40 N is…

A: The applied force F = 5.4 N. The particle’s mass is m = 0.8 kg. The amplitude A = 5 cm = 0.05 m. The…

Q: A block of mass 1.6 kg is held against a horizontal spring so that the spring is compressed 17 cm.…

A: The normal reaction acting on the block is: Therefore, the frictional force acting on the block is:…

Q: Dv 스크린샷 2022-03-30 오후 12.0 Qv 검색 스크린샷 2022-03-30 오후 12.00.55 20.0 g object is held against the free…

A: Given that, Mass of the block (m)= 20× 10-³ kg Spring constant (k)= 25 N/m Compression (x)= 0.1 m…

Q: A 1.68 kg block is held in place against the spring by a 39 NN horizontal external force. The…

A: Since the surface up to B is frictionless till the point B block moves with a velocity 2.1 m/s.Then…

Q: Problem 10: A simple pendulum with mass, m=1 kg and length, L=2.0 m is released by a push when the…

A: Given:length, L = 2 mAngle, θ = 45°Velocity, v = 3 m/s

Q: A block of mass 2 kg is attached to the end of a spring of force constant 180 kN/m as in fig. (a).…

A: Given data The mass of the block is m=2 kg The spring constant is K=180 kN/m The amplitude of the…

Q: Q: A L.00-kg block is moving at və = 10 m/s along a frictionless, horizontal surface toward a spring…

A: Given that --- m = 1.00 kg v = 10 m/sec k = 100 N/m Question --  distance ?

Q: A block of mass m = 2.00 kg is attached to a spring of force constant k = 4.95 x 102 N/m that lies…

A:

Q: A spring resting on a horizontal surface and attached to a mass of 0.60 kg. The spring is compressed…

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Q: A mass of 0.78 kg is is initially traveling at across a horizontal surface. It then reaches a spring…

A:

Q: A 50.0 cm long spring with spring constant 237 N/m has a mass 1.8 kg attached to it, and it can…

A: Given: The resting length of the spring: x0 = 50.0 cm. The spring constant: k = 237 N/m. The mass…

Q: a) Find the the work required to stretch the spring.   (b) Find the speed the block has as it…

A: Given, Mass of the block= 2 kg Force constant of the spring k=4.70×102 N/m The initial position of…

Q: A spring-powered dart gun is unstretched and has a spring constant 16.0 N/m. The spring is…

A: Data Given,  Spring constant ( k ) = 16 N/m Extension of the Spring  ( x ) = 8 cm             = 0.08…

Q: what is its speed (in m/s) when it is a distance of 10 cm from the equilibrium position

A: If we apply conservation of energy  Then  Initiay energy = final energy Initial energy is for…

Q: A 0. 2 ‑kilogram block is attached to an initially unstretched spring of force constant k = 180 N/m…

A: Given data The spring constant is, k=180 N/m The mass is. m=0.2 kg   The frequency of the…

Q: When a 0.34-kg block is suspended on a vertical spring, it causes it to stretch 2.90 cm. If the…

A: M= 0.34kg  x= 2.9cm = 0.029m y= 7.6cm = 0.076m

Q: A scene in a movie has a stuntman falling through a floor onto a bed in the room below. The plan is…

A:

Q: The 8-kg block is moving with an initial speed of 8 m/s. If the coefficient of kinetic friction…

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Q: OK, once again we have a pendulum, this time of length 1.03 m, which you release from rest at an…

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Q: A 5.0 kg block initially compresses a spring constant of 1650 N/m over a certain distance. After its…

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Q: A block of mass m = 2.00 kg is attached to a spring of force constant k = 4.35 x 102 N/m that lies…

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Q: A block of mass 0.5 kg on a horizontal surface is attached to a horizontal spring of negligible mass…

A: calculation

Q: A mass of 0.43 kg is is initially traveling at across a horizontal surface. It then reaches a spring…

A: Given: The mass of the object, m=0.43 kg Spring constant , K=138 N/m Initial speed of the object,…

Q: A block of mass 1.7 kg is attached to a horizontal spring that has a force constant 1100 N/m as…

A: Solution:

Q: "A particle with a mass of .7 kg is attached to a horizonal spring with a force constant of 40 N/m.…

A:

Q: A scene in a movie has a stuntman falling through a floor onto a bed in the room below. The plan is…

A:

Q: A mass of 0.8 kg is attached to a horizontal spring whose stiffness is 10 N/m. Friction is…

A: Since you have posted a question with multiple sub-parts, we will solve first three sub-parts for…

Spring Potential Energy

The potential energy is the energy possessed by a body by virtue of its position or the energy held by the object due to its position relative to other objects, its force like stresses, charge, and other factors affecting the particles of the body. The potential energy is the measure of the net work done by or on the body. The spring potential energy is the potential energy stored due to the deformation of an elastic spring and this elasticity is due to the stretched spring. The elasticity is the ability of a solid-state matter to come back to its equilibrium position or original position after any kind of external force is acted on it. It is also known as Elastic potential energy. The potential energy here is caused due to the displacement of the spring from its equilibrium position to another position and this potential energy is equal to the net work done due to the stretching of the spring. It also resembles the same mechanics of the oscillation of a simple pendulum, where due to the external force, the object moves from its equilibrium position to its maximum ends and the periodic motion continues till it comes back to the equilibrium position to rest.