[Kererences) INTERACTIVE EXAMPLE Nuclear Binding Energy I Calculate the binding energy per nucleon for the Fe nucleus. (Atomic masses: iron-56 = 55.9349 amu; hydrogen-1 = 1.0078 amu; mass of neutron = 1.0087 amu) HOW DO WE GET THERE? We must first calculate the mass defect (Am) for 56Fe. Since atomic masses (which include the electrons) are given, we must decide how to account for the electron mass: 55.9349 mass of Fe atom = mass of nucleus + 26 me 1.0078 mass of H atom = mass of nucleus + me Thus, since a 6Fe nucleus is "synthesized" from 26 protons and 30 neutrons, we see that Am = (55.9349 - 26 m.) - [26(1.0078 - me) + 30(1.0087)1. Solve for Am.
[Kererences) INTERACTIVE EXAMPLE Nuclear Binding Energy I Calculate the binding energy per nucleon for the Fe nucleus. (Atomic masses: iron-56 = 55.9349 amu; hydrogen-1 = 1.0078 amu; mass of neutron = 1.0087 amu) HOW DO WE GET THERE? We must first calculate the mass defect (Am) for 56Fe. Since atomic masses (which include the electrons) are given, we must decide how to account for the electron mass: 55.9349 mass of Fe atom = mass of nucleus + 26 me 1.0078 mass of H atom = mass of nucleus + me Thus, since a 6Fe nucleus is "synthesized" from 26 protons and 30 neutrons, we see that Am = (55.9349 - 26 m.) - [26(1.0078 - me) + 30(1.0087)1. Solve for Am.
Chemistry: An Atoms First Approach
2nd Edition
ISBN:9781305079243
Author:Steven S. Zumdahl, Susan A. Zumdahl
Publisher:Steven S. Zumdahl, Susan A. Zumdahl
Chapter18: The Nucleus: A Chemist's View
Section: Chapter Questions
Problem 78CWP
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![[References]
INTERACTIVE EXAMPLE Nuclear Binding Energy II
Calculate the binding energy per nucleon for the
Fe
nucleus. (Atomic masses: iron-56 = 55.9349 amu; hydrogen-1 = 1.0078 amu; mass of neutron = 1.0087 amu)
HOW DO WE GET THERE?
We must first calculate the mass defect (Am) for 56F.. Since atomic masses (which include the electrons) are given, we must decide how to
account for the electron mass:
55.9349 = mass of Fe atom = maSs of nucleus + 26 m.
1.0078 mass of H atom= mass of nucleus + me
Thus, since a 6Fe nucleus is "synthesized" from 26 protons and 30 neutrons, we see that Am = (55.9349 – 26 m.) - [26(1.0078 - m.) +
30(1.0087)].
Solve for Am.
Am =
amu](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F3b582a02-3e06-4fe8-94b6-b5b9e56861a2%2F35e32d57-9072-4601-82b7-7f3fdd97a053%2F74w94zo_processed.jpeg&w=3840&q=75)
Transcribed Image Text:[References]
INTERACTIVE EXAMPLE Nuclear Binding Energy II
Calculate the binding energy per nucleon for the
Fe
nucleus. (Atomic masses: iron-56 = 55.9349 amu; hydrogen-1 = 1.0078 amu; mass of neutron = 1.0087 amu)
HOW DO WE GET THERE?
We must first calculate the mass defect (Am) for 56F.. Since atomic masses (which include the electrons) are given, we must decide how to
account for the electron mass:
55.9349 = mass of Fe atom = maSs of nucleus + 26 m.
1.0078 mass of H atom= mass of nucleus + me
Thus, since a 6Fe nucleus is "synthesized" from 26 protons and 30 neutrons, we see that Am = (55.9349 – 26 m.) - [26(1.0078 - m.) +
30(1.0087)].
Solve for Am.
Am =
amu
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