L of Base Added pH Observer pH Calculated mmol of HC mmol NaOF mmol of Excess Total Volum M[H+] M[OH-] pOH 0.00 1.00 0.18 0.19 2.00 0.22 3.00 4.00 0.31 0.33 5.00 0.34 6.00 0.39 7.00 0.44 8.00 0.50 9.00 0.60 10.00 0.62 11.00 0.65 12.00 0.76 13.00 0.79 0.86 0.95 1.04 14.00 15.00 16.00 17.00 1.18
L of Base Added pH Observer pH Calculated mmol of HC mmol NaOF mmol of Excess Total Volum M[H+] M[OH-] pOH 0.00 1.00 0.18 0.19 2.00 0.22 3.00 4.00 0.31 0.33 5.00 0.34 6.00 0.39 7.00 0.44 8.00 0.50 9.00 0.60 10.00 0.62 11.00 0.65 12.00 0.76 13.00 0.79 0.86 0.95 1.04 14.00 15.00 16.00 17.00 1.18
Chapter14: Principles Of Neutralization Titrations
Section: Chapter Questions
Problem 14.38QAP
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I need help finding these calculations!
![Name
Parameter's
Lab Partner
Starting HCI conc. (M)
1.000 Assume exactly
CHEM 1B Lab
mL of HCI added
25.00
mL of NaOH to endpoint 21.5
SA/SB
HCI, NaOH
Starting NaOH conc. (M)
1.000 Calculated based on HCI
mL of Base Added pH Observer pH Calculated mmol of HC mmol NaOF mmol of Excess
Total Volumi M[H+]
M[OH-] pOH
0.00
0.18
1.00
0.19
2.00
0.22
3.00
0.31
4.00
0.33
0.34
0.39
5.00
6.00
7.00
0.44
8.00
0.50
9.00
0.60
10.00
0.62
11.00
0.65
0.76
0.79
0.86
12.00
13.00
14.00
15.00
0.95
16.00
1.04
17.00
1.18
10 00](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F5df190a0-0135-412b-8287-5a70a7487817%2Ff1e6d347-a3d7-4061-a6f4-c335f845a4c9%2F9qpgdru_processed.png&w=3840&q=75)
Transcribed Image Text:Name
Parameter's
Lab Partner
Starting HCI conc. (M)
1.000 Assume exactly
CHEM 1B Lab
mL of HCI added
25.00
mL of NaOH to endpoint 21.5
SA/SB
HCI, NaOH
Starting NaOH conc. (M)
1.000 Calculated based on HCI
mL of Base Added pH Observer pH Calculated mmol of HC mmol NaOF mmol of Excess
Total Volumi M[H+]
M[OH-] pOH
0.00
0.18
1.00
0.19
2.00
0.22
3.00
0.31
4.00
0.33
0.34
0.39
5.00
6.00
7.00
0.44
8.00
0.50
9.00
0.60
10.00
0.62
11.00
0.65
0.76
0.79
0.86
12.00
13.00
14.00
15.00
0.95
16.00
1.04
17.00
1.18
10 00
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