Lab Data Verify your concentration value. Did you report your data to the correct number of significant figures? Analytical wavelength for red dye (nm) Calibration curve Solution 1 23 4 5 Dye concentration (µM) 30.20 15.10 7.56 3.78 1.89 Molar absorptivity (μM-¹cm-¹) Unknown solution Absorbance Concentration of unknown red dye (µM) 501.4 Absorbance 0.800 0.441 0.186 0.111 0.027 0.0271 - X 0.341

Lab Data Verify your concentration value. Did you report your data to the correct number of significant figures? Analytical wavelength for red dye (nm) Calibration curve Solution 1 23 4 5 Dye concentration (µM) 30.20 15.10 7.56 3.78 1.89 Molar absorptivity (μM-¹cm-¹) Unknown solution Absorbance Concentration of unknown red dye (µM) 501.4 Absorbance 0.800 0.441 0.186 0.111 0.027 0.0271 - X 0.341

Fundamentals Of Analytical Chemistry

9th Edition

ISBN:9781285640686

Author:Skoog

Publisher:Skoog

Chapter27: Molecular Fluorescence Spectroscopy

Section: Chapter Questions

Problem 27.13QAP

See similar textbooks

Similar questions

If light machinery oil has a viscosity of 5E-2 Pa-s and density of 970 kg/m³ at 25°C, how long will it take for a sample to pass through a viscometer if water under this condition takes 1 min? Density of water is 1000 kg/m³ and its viscosity is 8.9E-4 Pa-s.A. 36.5 minB. 47.7 minC. 57.9 minD. 64.4 min
To determine the amount of copper and the identity of the copper compound in the unknown sample, a 100-mL solution containing 120.8 mg of the sample was initially prepared. Then, 5.00 mL of this solution was pipetted and diluted with deionized water in another 100-mL volumetric flask. The absorbance of this diluted solution was determined three times at the analytical wavelength. The data is in the table below. Unknown sample Trial 1 Trial 2 Trial 3 Absorbance (AU) 0.378 0.379 0.377 What is the corrected absorbance?
To determine the amount of copper and the identity of the copper compound in the unknown sample, a 100-mL solution containing 120.8 mg of the sample was initially prepared. Then, 5.00 mL of this solution was pipetted and diluted with deionized water in another 100-mL volumetric flask. The absorbance of this diluted solution was determined three times at the analytical wavelength. The data is in the table below. Unknown sample Trial 1 Trial 2 Trial 3 Absorbance (AU) 0.388 0.389 0.388 What is the Corrected Absorbance of each trial? How do you get the corrected absorbance?
To determine the amount of copper and the identity of the copper compound in the unknown sample, a 100-mL solution containing 120.8 mg of the sample was initially prepared. Then, 5.00 mL of this solution was pipetted and diluted with deionized water in another 100-mL volumetric flask. The absorbance of this diluted solution was determined three times at the analytical wavelength. The data is in the table below. Unknown sample Trial 1 Trial 2 Trial 3 Absorbance (AU) 0.388 0.389 0.388 What is the concentration of Cu in analyzed solution (mg/L) for each trial?
As part of an analytical chemistry laboratory course, a student measured the Ca2+ content in two water samples, city-supplied drinking water and well-supplied drinking water, using two different analytical methods, flame atomic absorption spectrometry (FAAS) and EDTA complexometric titration. The results of this experiment are given in the table as the mean Ca2+concentration (?¯) and standard deviation (?) in parts per million (ppm). Each sample was measured five times (n=5) by each method. Method City-Supplied Drinking Water (?¯±?x¯±s) Well-Supplied Drinking Water (?¯±?x¯±s) FAAS 57.57±0.68 ppm 64.77±0.70 ppm EDTA titration 58.32±0.96 ppm 65.62±0.97 ppm Method Comparison: For each drinking water sample (city and well), compare the Ca2+ content measured by FAAS and EDTA titration. Calculate the ? value for each sample. Do the methods produce statistically different results at the 95% confidence level when measuring the Ca2+content of the city-supplied drinking water? Do the…
To determine the amount of copper and the identity of the copper compound in the unknown sample, a 100-mL solution containing 120.8 mg of the sample was initially prepared. Then, 5.00 mL of this solution was pipetted and diluted with deionized water in another 100-mL volumetric flask. The absorbance of this diluted solution was determined three times at the analytical wavelength. The data is in the table below. Unknown sample Trial 1 Trial 2 Trial 3 Absorbance (AU) 0.375 0.374 0.376 What is the concentrartion of Cu in the analyzed solution?
6. Give one advantage of contact printing over proximity printing. Giveone disadvantage of contact printing compared to proximity printing. 7. A pattern is to be printed using deep UV radiation for the exposure.Should the mask material be made of glass or quartz? Why? 8. Pattern resolution is increased by decreasing exposure wavelength. Ifa projection printer is used, will the objective lens need to be redesigned?Why or why not? 9. In a clean room rated at class 1000, on the average, how many particles percubic meter are there? Assume a particle size of 1 um. 10. After exposing a resist, why is it a good idea to bake the resist? 11. When positive resist is exposed, what happens to its solubility? 12.With respect to transferring a pattern to the resist, what is meant byresolution? 13.What kind of cleaning process is best suited for a wafer before it isoxidized?
You are trying to come up with a drug to inhibit the activity of an enzyme thought to have a role in liver disease. In the laboratory the enzyme was shown to have a Km of 1.0 x 10-6 M and Vmax of 0.1 micromoles/min.mg measured at room temperature. You developed a competitive inhibitor. In the presence of 5.0 x 10-5 M inhibitor, the apparent Km of the enzyme was found to be 1.5 x 10-5 M. What is the Ki of the inhibitor?
Alfred was tasked to synthesize at least 250.0 ppm of his novel gold nanoparticles (AuNP’s) to be able to perform experiments about the efficacy of AuNP for viral detection. He decided to check whether he still needed to synthesize more or not using a UV Vis spectrophotometer. Fortunately, he already prepared a 100.0 ppm AuNP standard solution beforehand. He got a different aliquot of the standard, added stabilizing solutions, and diluted them to 10.0 mL for the determination of absorbance. Data he obtained is shown below. Table 1. Calibration curve data for AuNP v of 100.0 ppm AuNP standard, mL Absorbance 0.00 0.200 0.50 0.450 1.00 0.510 1.50 0.600 2.00 0.680 3.00 0.810 4.00 0.950 After obtaining the calibration curve, he got a 3.00-mL aliquot of the pre-prepared solution, added stabilizing solution, and diluted it to 10 mL. He got 10mL of the final solution and determined its absorbance to be 0.650. The absorbance of the blank…
How can gold Nanoparticle influence tetrapyrolic macrocylcle like porphyrin in photo dynamic theraphy ?
The absorbance of a 0.00004 M potassium thiocyanate solution, (KSCN), is measured as 0.632 in a 1.00 cm cell. What is the molar absorptivity, ε ? Report your answer with the correct number of significant figures in scientific notation (accepted format 1.23*10^3). Enter numbers only; do not enter units.
Please create a caption for this table. Solution NaCl Conc. (%) Osmolality (mOsm) % transmittance Absorbance % hemolysis % crenation C distilled 0 0 0.001029 4.987584625 100 0.03354 1 0.177179111 54.61 0.001551 4.809388202 96.42720001 0.05837 2 0.297126222 91.58 0.01012 3.994819487 80.09527231 0.08444 3 0.442542222 136.4 3.849 1.414652089 28.3634704 0.134 4 0.590164444 181.9 64.8 0.188424994 3.777880643 0.2125 5 0.74752 230.4 95.64 0.019360433 0.388172513 0.3368 6 0.89644 276.3 99.56 0.001915112 0.038397585 0.5336 7 1.095648889 337.7 99.98 8.68676E-05 0.001741676 0.9834 8 1.336711111 412 100 0 0 2.1 9 1.755568889 541.1 100 0 0 7.9 10 2.674395556 824.3 100 0 0 57.83 11 4.490211111 1384 100 0 0 99.72