Laboratory compaction test results on a clayey soil are listed in the table below.Moisture content (%) Dry unit weight (kN/m³)614.80817.45918.521118.91218.51416.9The following are the results of a field unit weight determination test on the same soil with the sand cone method:Calibrated dry density of Ottawa sand = 1,560 kg/m³Calibrated mass of Ottawa sand to fill the cone = 0.565 kgMass of jar + cone + sand (before use) = 7.59 kgMass of jar + cone + sand (after use) = 4.78 kgMass of moist soil from hole = 2.85 kgMoisture content of moist soil = 15.2%Determine:a. Dry unit weight of compaction in the field.(Enter your answer to three significant figures.)Ya =]kN/m³b. Relative compaction in the field.(Enter your answer to two significant figures.)R =|%

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Laboratory compaction test results on a clayey soil are listed in the table below. Moisture content (%) Dry unit weight (kN /m³) 14.80 17.45 9 18.52 11 18.9 12 18.5 14 16.9 The following are the results of a field unit weight determination test on the same soil with the sand cone method: Calibrated dry density of Ottawa sand = 1,560 kg/m³ Calibrated mass of Ottawa sand to fill the cone = 0.565 kg 6,

Laboratory compaction test results on a clayey soil are listed in the table below. Moisture content (%) Dry unit weight (kN /m³) 14.80 17.45 9 18.52 11 18.9 12 18.5 14 16.9 The following are the results of a field unit weight determination test on the same soil with the sand cone method: Calibrated dry density of Ottawa sand = 1,560 kg/m³ Calibrated mass of Ottawa sand to fill the cone = 0.565 kg 6,

Principles of Geotechnical Engineering (MindTap Course List)

9th Edition

ISBN:9781305970939

Author:Braja M. Das, Khaled Sobhan

Publisher:Braja M. Das, Khaled Sobhan

Chapter6: Soil Compaction

Section: Chapter Questions

Problem 6.7P

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8 The following are results of a field unit weight determination test using sand cone method: Volume of hole = 0.0019 m3 Mass of moist soil from hole = 3.24 kg Water content = 12.01% Max. dry unit weight from a laboratory compaction test = 19.70 kN/m3 Determine the relative compaction, in percent. Round off to two decimal places. Hint: Relative compaction = Field dry unit weight / Max dry unit weight (lab)
The laboratory compaction test of a certain type of soil gives a maximum dry density of 1.486 g/cc3 with an optimum moisture content of 12.5%. Determine the relative compaction of the soil using the following results of a filed unit weight determination test using sand cone method. Volume of soil excavated from the hole = 0.001337 m3 Weight of moist soil from the hole = 2220 g Weight of oven dried soil = 1890 g Select one: a. 97.25 b. 95.10 c. 90.34 d. 88.41
2. Sand cone equipment is used to perform a field density test on a compacted earth fill. Sand is used in the cone and is known to have a bulk density of 15.74 kN/m3 . Soil sample dug from test hole, (wet weight) = 20.601 N Dry weight of soil sample = 17.926 N Weight of sand (sand cone) to fill test hole = 16.503 N Determine the in-place dry density of the tested soil (Ans: 17.57 kN/m3) Determine the water content (Ans: 15%) Compute the percentage of compaction of the tested soil if the laboratory moisture-density curve indicates a dry density of 18.10 kN/m3 and an optimum moisture content of 13%. (Ans: 97.07%)
2. Sand cone equipment is used to perform a field density test on a compacted earth fill. Sand is used in the cone and is known to have a bulk density of 15.74 kN/ . Soil sample dug from test hole, (wet weight) = 20.601 N Dry weight of soil sample = 17.926 N Weight of sand (sand cone) to fill test hole = 16.503 N Determine the in-place dry density of the tested soil (Ans: 17.57 kN/ ) Determine the water content (Ans: 15%) Compute the percentage of compaction of the tested soil if the laboratory moisture-density curve indicates a dry density of 18.10 kN and an optimum moisture content of 13%. (Ans: 97.07%)
The following are results of a field unit weight determination test using sand cone method: Volume of hole = 0.0019 m3 Mass of moist soil from hole = 3.48 kg Water content = 12.43% Max. dry unit weight from a laboratory compaction test = 19.56 kN/m3 Determine the relative compaction, in percent. Hint: Relative compaction = Field dry unit weight / Max dry unit weight (lab)
The following are the results of a field unit weight determination test performed on the soil by means of the sand cone method. Calibrated dry density of Ottawa sand = 1570 kg/m3 Calibrated mass of Ottawa sand to fill the cone = 0.545 kg Mass of jar + cone + sand (before use) = 7.59 kg Mass of jar + cone + sand (after use) = 4.78 kg Mass of moist soil dug from hole = 3.007 kg Water content of moist soil = 10.2% Max dry unit weight = 19 kN/m3 Find the dry unit weight in kN/m3.
The laboratory compaction test of a certain type of soil gives a maximum dry density of 1486 g/m3 with an optimum moisture content of 12.5%. The following are the results of a field unit weight determination test using sand cone method. Volume of soil excavated from the hole = 0.001337 m3 Weight of soil from the hole when wet = 2220 g Weight of soil from the hole when dried = 1890 g Determine the field unit weight of soil in g/cm3. Determine the relative compaction, then tell whether it is within the allowable range for relative compaction of 95 ± 0.20?
Following are the results of a field unit-weight determination test performed on the same soil by means of the sand cone method: -Calibrated dry unit weight of Ottawa sand = 15.4019 kn/m3 -Calibrated weight of Ottawa sand to fill the cone = 5.3496 N -Weightof jar + cone + sand (before use) = 74.451 N -Weightof jar + cone + sand (after use) = 46.886 N -Weight of moist soil from hole = 29.509 N -Moisture content of moist soil = 10.21% DETERMINE AND SHOW COMPLETE SOLUTION 1. Dry density of compaction in the field in kg/cu.m.
A sand-cone in place unit test was conducted on the field during the construction of a proposed embankment. The following data were obtained. moisture content=12.8% weight of sand to fill the funnel=320 g weight of wet soil from test hole=750 g unit weight of sand=15.4 kN/m3 weight of sand used to fill test hole and funnel of sand-cone device=870 g a) compute the wet unit weight of soil (Ans. 21.14 kN/m3) b) compute the dry unit weight of the compacted soil (Ans. 18.74 kN/m3) c) compute the relative compaction in the field if the maximum dry unit weight of the soil is 21.3 kN/m3. (Ans. 87.98%)
6. The relative compaction of a sand in the field is 93.5%. Given that dry unit weight max = 16.98 kN/m3 and dry unit weight min = 14.46 kN/m3. What is the dry unit weights in the field? (Ans: 15.88 kN/m3) What is the relative density compaction? (Ans: 60.1%) What is the water content of the sand if the moist unit weight is 18.42 kn/m3. (Ans: 16%)
Subject: Soil Mechanics Provide solution and diagram. A direct shear test, when conducted on a remolded sample of sand, gave the following observations at the time of failure: Normal load = 288 N; shear load = 173 N. The cross-sectional area of the sample = 36 cm2. Determine the angle of internal friction in degrees. a. 29 b. 27 c. 31 d. 33
Sand is used in the cone is known to have a bulk density of 15.74 kN/m3 Wet weight=20.601 N Dry weight =17.926 N Weight of sand to fill test hole =16.053 N a) Determine the in-place dry density of the tested soil (Ans. 17.57 kN/m3) b) Determine the water content (Ans. 15%) c) Compute the percentage of compaction of the tested soil if the laboratory moisture density curve indicates a dry density of 18.1 kN/m3 and an optimum moisture content of 13%. (Ans. 97.07%)