Let be a function that allows continuous second partial derivatives , we know that: Vf(x,y) = (36x³ – 4xy² ,16y³ – 4x²y – 32y² + 16y) fxx = = 108x? – 4y2 fyy = 48y2 – 4x² – 64y + 16 - fxy = -8xy Consider the critic point (a,b) with negative X coordinates , that point generates a saddle point. What's the value for a and b?

Advanced Engineering Mathematics
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ISBN:9780470458365
Author:Erwin Kreyszig
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Chapter2: Second-order Linear Odes
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Let be a function that allows continuous second partial derivatives , we know that:
Vf(x,y) = (36x³ – 4xy² ,16y³ – 4x²y – 32y2 + 16y)
%3D
fxx %3D 108х? — 4у?
fyy = 48y? – 4x² – 64y + 16
fxу %3D —8ху
Consider the critic point (a,b) with negative X coordinates , that point generates a saddle point.
What's the value for a and b?
Transcribed Image Text:Let be a function that allows continuous second partial derivatives , we know that: Vf(x,y) = (36x³ – 4xy² ,16y³ – 4x²y – 32y2 + 16y) %3D fxx %3D 108х? — 4у? fyy = 48y? – 4x² – 64y + 16 fxу %3D —8ху Consider the critic point (a,b) with negative X coordinates , that point generates a saddle point. What's the value for a and b?
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