Let F(r, y, 2) = 3z7- 2y 3 – (x + y) E. For each of the surfaces in Parts (a)-(d), say whether the flux of F through the surface is positive, negative, or zero. In each case, the orientation of the surface is indicated by the given normal vector. (a) (b) (c) (d)

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Chapter6: Gauss's Law
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Problem 7CQ: (a) If the electric flux through a closed surface is zero, is the electric field necessarily zero at...
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3. Let F(r, y, z) = 3zi – 2y3 – (x + y) k. For each of the surfaces in Parts (a)-(d), say whether the flux of F
through the surface is positive, negative, or zero. In cach case, the orientation of the surface is indicated by
the given normal vector.
(a)
(b)
(c)
(d)
Transcribed Image Text:3. Let F(r, y, z) = 3zi – 2y3 – (x + y) k. For each of the surfaces in Parts (a)-(d), say whether the flux of F through the surface is positive, negative, or zero. In cach case, the orientation of the surface is indicated by the given normal vector. (a) (b) (c) (d)
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Hi. Since you have posted a question with multiple subparts and not specified which subparts you want us to solve, we will solve the first three subparts for you. If you want the remaining subpart to be answered, please resubmit the question and specify the subpart that needs to be solved.

 

The flux (φ) of a vector field (F) through an area (A) can be calculated as follows:

 

φ=AF·dA

 

Here, dA is the vector area element.

Step 2

(a)

The area element (dAa = dydz) in the diagram is along the positive x-axis. The unit vector (i) is along the positive x-axis. The plane has the limits (y > 0, z > 0).

Determine the flux (φa) in this case in the integral form to check its sign as follows:

 

φa=F·dAa=y>0, z>03zi^-2yj^-x+yk^·dydzi^=y>0dyz>03zdz>0

 

Hence, the flux in this case is positive.

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