Let L₁ = {aa, bb},L₂ = {A, a, aa},L3 = {x | x = {a,b}* ^ |x| ≤ 3} ={A, a, b, aa, ab, ba, bb, aaa, aab, aba, abb, baa, bab, bba, bbb}.Evaluate:(L₁n L3) · L2 =•

The question asks us to evaluate the following expression:(L₁ ∩ L₃) L₂where:L₁ = {aa, bb}L₂ = {Λ, α,…

Answered: Let L₁ = {aa, bb}, L₂ = {A, a, aa}, L3…

Systems Architecture

7th Edition

ISBN:9781305080195

Author:Stephen D. Burd

Publisher:Stephen D. Burd

Chapter10: Application Development

Section: Chapter Questions

Problem 6VE

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1. Big-O Notation Let f and g be functions from the set of integers or the set of real numbers to the set of real numbers. We say that f ( x ) is O ( g ( x ) ), read as "f ( x ) is big-oh of g ( x )", if there are constants C and k such that | f ( x ) | ≤ C | g ( x ) | whenever x > k. (a) Show that f(x) = x2 + 2x + 1 is O(x2) Solution: When x>1; ? 2 (1 + 2 ? + 1 ? 2 ) < ? 2 (1 + 2 1 + 1 1 2 ) = 4? 2 So, ??? ? > 1, ? 2 + 2? + 1 < 4? 2 From the definition 0 ≤ f(x) ≤ cg(x) for x≥1 Hence, for N0 = 1; c=4; and g(x)=x2 for N0 = 2; c=3; and g(x)=x2 for N0 = 3; c=2; and g(x)=x2 … Therefore, ? ? + ?? + ? = ?(? ? ) O(g(x)) = {f(x)|there exist positive constant c and N0 such that 0 ≤ f(x) ≤ cg(x) for all x≥N0} 2. Show that 7x2 is O(x3). 3. Suppose there are x number of boxes to be delivered to x number of household that is 2km apart, what is the distance travelled by the transport delivery service? 4. In number 3, suppose that each boxes…
Q. No. 2: Let Σ = {a, b, c}. a. Draw a DFSA that rejects all words for which the last two letters match. b. Draw a DFSA that rejects all words for which the first two letters match.
Assume the following scoring matrix. A T C G - A 1 -1 -1 -2 -1 T 1 -1 -1 -1 C 2 -1 -1 G 1 -1 Fill out the dynamic programming table for the global alignment between sequences v = TAGCTCCG and w = GCATCCA using the scoring matrix above. Use the following recursive scoring formula. w= G C A T C C A 0 1 2 3 4 5 6 7 v= 0 T 1 A 2 G 3 C 4 T 5 C 6 C 7 G 8 What is the score and global alignment between v and w?
QUESTION 4 State whether the following statement is true or false : there exists x element of R comma space there exists y space element of R space left parenthesis x plus y equals 2 right parenthesis space logical and left parenthesis x minus y equals 3 right parenthesis True False
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Hi! I get this error message with this code. Can you help me? # Write your solution here def who_won(game_board): # Initialize counters for each player's encircled area player1_area = 0 player2_area = 0 # Iterate through each square in the game board for i in range(len(game_board)): for j in range(len(game_board[i])): # Check if the square is encircled by player 1's game pieces if game_board[i][j] == 1: # Check if all four surrounding squares are also player 1's game pieces if (i > 0 and game_board[i-1][j] == 1) and (i < len(game_board)-1 and game_board[i+1][j] == 1) and (j > 0 and game_board[i][j-1] == 1) and (j < len(game_board[i])-1 and game_board[i][j+1] == 1): player1_area += 1 # Check if the square is encircled by player 2's game pieces elif game_board[i][j] == 2: # Check if all four surrounding squares are also player…
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Write a classifier algorithm for p(Y |X,α)
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PYTHON DATASET given x = np.array([i*np.pi/180 for i in range(60,300,4)]) np.random.seed(10) #Setting seed for reproducibility y = 4*x + 7 + np.random.normal(0,3,len(x)) Write a function inspired by sklearn’s polynomial preprocessing: (https://scikit-learn.org/stable/modules/generated/sklearn.preprocessing.PolynomialFeatures.html) your function should have: degree and include bias parameters only. For this assignment, assume that input is a 1-dimensional numpy array. For example, if an input sample is np.array([a, b]), the degree-2 polynomial features with "include_bias=True" are [1, a, b, a2, b2].
Given g = {(1,c),(2,a),(3,d)}, a function from X = {1,2,3} to Y = {a,b,c,d}, and f = {(a,r),(b,p),(c,δ),(d,r)}, a function from Y to Z = {p, β, r, δ}, write f o g as a set of ordered pairs.
Simplify the following assertions (so that ¬ does not appear). a) ¬((∃a ∈ A,((∀b ∈ B, a × b = 2) ⇒ (∃b ∈ B, a + b ≠ 3))) & (∀a ∈ A, ∃b ∈ B, ((a+b = 5)∨(a−b = 5)))) b) ¬((∃a ∈ A, ∀b ∈ B, ((a + b = 3) ∨ (a - b = 3))) & (∀a ∈ A, ((∃b ∈ B, a × b = 7) ⇒ (∀b ∈ B, a + b ≠ 4)))) c) ¬((∃a ∈ A, ∀b ∈ B, ((a + b = 2) & (a - b = 2))) ∨ (∀a ∈ A, ((∃b ∈ B, a + b = 7) ⇒ (∀b ∈ B, a + b = 5)))) d) ¬((∀a ∈ A,((∃b ∈ B, a - b = 4) ∨ (∀b ∈ B, a + b ≠ 2))) & (∃a ∈ A, ∀b ∈ B, ((a+b = 5)∨(a−b = 5))))

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Let L₁ = {aa, bb}, L₂ = {A, a, aa}, L3 = {x | x = {a,b}* ^ |x| ≤ 3} = {A, a, b, aa, ab, ba, bb, aaa, aab, aba, abb, baa, bab, bba, bbb}. Evaluate: (L₁n L3) · L2 = •