function problem13() { var outputObj = document.getElementById("output"); var inputNumber = parseInt(document.getElementById("number Input").value); outputObj.innerHTML = "number: " + inputNumber; // Add line breaks for space outputObj.innerHTML += ""; // Generate the sequence based on the input number for (var i = 1; i <= inputNumber; i++) { var result = Math.pow(2, 1) - 1; outputObj.innerHTML += result; // Add a comma if it's not the last number if (i < inputNumber) { outputObj.innerHTML += ", } } // Add line breaks for space outputObj.innerHTML += ""; // Program ended message outputObj.innerHTML += "Program ended";

Scrabble Scrabble is a game where players get points by spelling words. Words are scored by adding together the point values of each individual letter. Define a function scrabble_score (word:str) -> int that takes a string word as input and returns the equivalent scrabble score for that word. score = {"a": 1, "c": 3, "f": 4, "i": 1, "1": 1, "o": 1, "r": 1, "u": 1, "t": 1, "x": 8, "z": 10} For example, "b": 3, "h": 4, "n": 1, Your Answer: == 20 assert scrabble_score("quick") assert scrabble_score("code") == 7 1 # Put your answer here 2 Submit "e": 1, "d": 2, "g": 2, "k": 5, "j": 8, "m": 3, "q": 10, "p": 3, "s": 1, "w": 4, "v": 4, "y": 4,

JS Write a function named list_concat that has a single parameter. This parameter will be a list/array. The parameter's entries will be strings. Your function needs to return a string. The returned string's value should be the concatention of all of the entries in the parameter with a space after each entry. Sample test cases: list_concat(["single"]) evaluates to "single list_concat(["limit", "break", "ready"]) evaluates to "limit break ready

The show_sequence function at below is part of chapter 3 program.  What kind of passing does this function us and why? void show_sequence(sequence display) // Library facilities used: iostream{    for (display.start( ); display.is_item( ); display.advance( ))    cout << display.current( ) << endl;} Group of answer choices It uses a value parameter.  The reason is the advancing of the current element through the sequence would alter the actual argument.  That is what we want. It uses a value parameter.  The reason is the we don't want the advancing of the current element through the sequence to alter the actual argument. It uses a geneeral parameter.  The reason is the we don't want the advancing of the current element through the sequence to alter the actual argument. It uses a reference parameter.  The reason is the we don't want the advancing of the current element through the sequence to alter the actual argument. It uses a reference parameter.   The reason is…

The following array of structures is used to hold data of your IPC144 grade center   strcut grades {char name[101]; unsigned final; unsigned total;} struct grades myClass[25];     Write a function that gets the class grades array as a parameter and prints the list of people who passed the course (a student passes a course if he/she passes the final as well as the total) and their total mark. The function should also print the class average at the end (based on the total marks)   void printPassedAverage(struct grades myClass, int size)   The output should be like this   Students passed:--------------------- John Smith      85 Jane Doe         65 Roy Crowe      80 Julia Stuart      55 Rob Gates       60   Class average: 69

#include using namespace std; struct ListNode { string data; ListNode *next; }; int main() { ListNode *p, *list; list = new ListNode; list->data = "New York"; p new ListNode; p->data = "Boston"; list->next = p; p->next = new ListNode; p->next->data = "Houston"; p->next->next = nullptr; // new code goes here Which of the following code correctly deletes the node with value "Boston" from the list when added at point of insertion indicated above? O list->next = p; delete p; O p = list->next; %3D list->next = p->next; delete p; p = list->next; list = p->next; delete p; O None of these O p = list->next; %3D list->next = p; %3D delete p;

Which function members are mutators?

1c) Average sentence length We will create a function (avg_sentence_len) to calculate the average sentence length across a piece of text. This function should take text as an input parameter. Within this function: sentences: Use the split() string method to split the input text at every '.'. This will split the text into a list of sentences. Store this in the variable sentences. To keep things simple, we will consider every "." as a sentence separator. (This decision could lead to misleading answers. For example, "Hello Dr. Jacob." is actually a single sentence, but our function will consider this 2 separate sentences). words: Use the split() method to split the input text into a list of separate words, storing this in words. Again, to limit complexity, we will assume that all words are separated by a single space (" "). (So, while "I am going.to see you later" actually has 7 words, since there is no space after the ".", so we will assume the this to contain 6 separate words in our…

void getVectorSize(int& size); void readData(vector<Highscore>& scores); void sortData(vector<Highscore>& scores); vector<Highscore>::iterator findLocationOfLargest( const vector<Highscore>::iterator startingLocation, const vector<Highscore>::iterator endingLocation); void displayData(const vector<Highscore>& scores); The size parameter from the given code won't be needed now, since a vector knows its own size. Notice that the findLocationOfLargest() function does not need the vector itself as a parameter, since you can access the vector using the provided iterator parameters. The name field in the struct must still be a c-string The focus of this assignment is to use iterators. You must use iterators wherever possible to access the vector. As a result, you must not use square brackets, the push_back() function, the at() function, etc. Also, the word "index" shouldn't appear in your code anywhere. You won't get full credit if…