lim x-0+ \x 1 = lim x2, 1 lim x0+ x2 1 = +0 - (+0) = 0 - - - -- %3D x-0+ x

Q: lim x-->-1, lim x-->-1+, lim x-->-1-,

A:

Q: lim tangx X->즐 (쫄-x n2.

A: Given: limx→π2tan2xπ2-x 00 form If limx→afxg(x) is of the form 00, then we use L'Hospital's rule.…

Q: lim ²+2x+4 2-1 31²-2+8 LIMIT VALUE: lim 2-0 LIMIT VALUE: lim x-1 LIMIT VALUE: +6-√6 z ²+81-5 3x+7

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Q: Оuestion: 2 Use the numerical method to find lim 3-x

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Q: Calculus Question

A: Option e is false .  Please rate helpful and feel free to ask any query about any part.

Q: lim [(x²-In(x + 1)) cot x] x-0-

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Q: 1. lim x2 +1 = 2 ズ→0 (x-2)2 2. lim X2 (x-2)(x+2) 3. lim (5 -)

A: Put the limit in function

Q: lim 3x/x+1 = 3 x--> infinity, ε = 0.5, find smallest N > 0

A: Answer

Q: 15. lim 0 x-2 |x-2 16. lim x-2 17. lim -2r+1

A: 15- Given- limx→0x-2x-2 To Solve- The above expression.

Q: lim x approaches 2/3 .............. (8 - 3s)(2s - 1)

A: We have to find the limit: limx→238-3s2s-1 This is determinate form of limit so we just have to put…

Q: lim- x-0 X

A: Given :limx→05x

Q: lim x approaches 9 ........ [(x)^1/2 - 3]/(x - 9)

A: limx→9 x-3(x-9)When put x=9, then00 form occur

Q: Lim x->4 (x2-3x-4)/ (x-4)

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Q: lim 1/x^2 - 1 = infinity x--> 1+, M = 1000, find largest δ > 0

A: Use the definition of limit

Q: x'- 16 • lim x2 X-2 x'- x- 5x - 2 • lim (x +1) Xー1 M + x - 1 • lim

A: Here, we need to find the limit of the given expressions. (i)            limx→ 2x4-16x-2=limx→…

Q: Lim 1- Cosx て X-)0

A: Given: L=limx→01-cosxsin2x We know that 1-cos2x=2sin2x…

Q: 2) lim-(x-) ta tan x

A:

Q: 2 メーズ Lim メ→&-X

A: Evaluate: limx→∞ex-x2ex-x

Q: lim x approaches 5  ........ x - 5/[ x2 - 25]

A: Limit of the function is value that function seems to approach as x approaches certain value.

Q: 1 f. lim-( x-→0 x`x+2 2 (1+x) -/ g. lim

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Q: Sketch the graph of a function with the given limits.

A: let f(x) be a function, has the propertieslimx→1f(x)=∞ , limx→3-f(x)=0 , limx→3+f(x)=-∞

Q: 1.) lim √5-x 2.) lim √5-x 1-5 3.) lim√√5-x

A: We have to find the limit.

Q: lim x approaches 6 .............. (x^3 - 2x^2 + 4x + 8)

A: We need to lim x approaches 6 .............. (x^3 - 2x^2 + 4x + 8)

Q: 28. lim x -2 x-4 V2+パ-V2-x 29. lim

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Q: lim.                          x^5 x --> - infinity

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Q: 4. lim 1000 x-1000 5. lim X--2 x

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Q: lim x-7 回团 lim x-7 2→6+ x-6 lim -7 x→6 x-6

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Q: lim x->1 x4-1/x-1

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Q: x2-4 1) lim x-2 x-2 sin 2x 2) lim 1 3) lim(-- x0 x V

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Q: limx → 1 (x-2) / (x-1)2 ii.  limx → 1 (x2-1) / (x-1) iii. limx → 1  |x-1| / (x-1)

A:

Q: 1. lim (4x – 7) 2. lim (x3- 2x² + x - 5) X-1 3. lim (x2 - x + 3)(2x – 1) X-2

A: 1. limx→04x-72. limx→1x3-2x2+x-53. limx→-2x2-x+32x-1 Note:     Multiple sub part are given, we are…

Q: lim x-->3 f(x)=8 and lim x--->3 g(x)= -4 1) limx--->3 (3f(x)-5g(x)) 2) lim x---> G(x)^3 + 50 /  (…

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Q: 1.) lim 5-x 2.) lim 5-x 3.) lim 5-x

A: Given query is to find indicated limit.

Q: lim x->0 ((x3-x2)/(3x2+x))

A: Answer and explanation is given below

Q: lim x->0 (x2 +x)

A: Given,          limx→0x2+x

Q: 2) lim- x) Tanx

A: The given limit is              limx→π2π2-xTanx we know,     Tanx= sinxcosx

Q: lim x^1/6-1/x^1/3-1 x->1

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Q: x2 – 2 3. lim x→2+ [x – x | x2 + 2x 4. lim x→0 x2 2.x - x2 5. lim x→2 10x + 16 - x2 – x – 2 - -

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Q: lim Vx2+1-Va²+1 4-, 5- lim 1 x+2 6-, lim sin 3x X-a -

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Q: 5. ) lim x-0 x +1 x2 +9 (b) lim (7 -2) 1 x2 +9 (c) lim- (d)lim n-00

A:

Q: 91_در lim 2-3 z²+4z-21 LIMIT VALUE: lim 2--1 LIMIT VALUE: lim (x³ +7x² - 2x + 4) 2-2 LIMIT VALUE:…

A: Solved below

Q: lim (1 + x→0- X

A:

Q: 1.) lim 3* x-2 2.) lim (2x+¹ -3) x-2

A: Given: 1.limx→23x2.limx→22x+1-3

Q: lim (√x²+4) x--> 0

A: limx→0x2+4

Q: lim x>-3- x² +2xr-3 a. X- 7X b. lim x>-3+ x2 +2x-3 lim x>-3 x² +2x-3 C. X- ,X

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Q: lim (2x²+x-1) 2-0 LIMIT VALUE: 2²-4 lim 2-0 2+8 LIMIT VALUE: LIMIT VALUE: 9-z lim 2-9 3-√√2

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Q: 1. limx→−1−  F(x)= 2.lim x--->-1+  F(x)= 3. limx-->-1  F(x)= 4.F(-1)=

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Q: lim f(x)=3 x-->5- and lim f(x)=1 x-->5+

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Q: lim x→8 f(x) = 4  and limx→8  g(x)=8   , evaluate limx→8  f(x) +g(x)  /7f(x)   Limit =

A: Given,

Limits

When it comes to calculus, limits are considered to be a very important topic of discussion. The main importance of limit lies in expressing the value of a function as it gets closer to a certain value. Also, limits can help you to understand other topics, such as continuity and differentiability better. In a broader sense, every calculus notion is a limit. Other branches of calculus have also been derived from limits.