Listed in the data table are amounts of strontium-90 (in millibecquerels, or mBq, per gram of calcium) in a simple random sample of baby teeth obtained from residents in two cities. Assume that the two samples are independent simple random samples selected from normally distributed populations. Do not assume that the population standard deviations are equal. Complete parts (a) and (b) below. E Click the icon to view the data table of strontium-90 amounts. a. Use a 0.05 significance level to test the claim that the mean amount of strontium-90 from city #1 residents is greater than the mean amount from city #2 residents. What are the null and alternative hypotheses? Assume that population 1 consists of amounts from city #1 levels and population 2 consists of amounts from city #2. O A. Ho: H1 SH2 H: H1 > H2 O B. Ho: H1 H2 H:H > H2 OC. Ho: H1 = H2 H: H1 # H2 D. Ho: H1 =H2 H: H1> H2 The test statistic is 1.54. (Round to two decimal places as needed.) The P-value is 0.067. (Round to three decimal places as needed.) State the conclusion for the test. A. Fail to reject the null hypothesis. There is not sufficient evidence to support the claim that the mean amount of strontium-90 from city #1 residents is greater. O B. Reject the null hypothesis. There is not sufficient evidence to support the claim that the mean amount of strontium-90 from city #1 residents is greater. O C. Reject the null hypothesis. There is sufficient evidence to support the claim that the mean amount of strontium-90 from city #1 residents is greater. O D. Fail to reject the null hypothesis. There is sufficient evidence to support the claim that the mean amount of strontium-90 from city #1 residents is greater. b. Construct a confidence interval suitable for testing the claim that the mean amount of strontium-90 from city #1 residents is greater than the mean amount from city ## residents. mBq < H1 - H2 (Round to two decimal places as needed.) mBq
Listed in the data table are amounts of strontium-90 (in millibecquerels, or mBq, per gram of calcium) in a simple random sample of baby teeth obtained from residents in two cities. Assume that the two samples are independent simple random samples selected from normally distributed populations. Do not assume that the population standard deviations are equal. Complete parts (a) and (b) below. E Click the icon to view the data table of strontium-90 amounts. a. Use a 0.05 significance level to test the claim that the mean amount of strontium-90 from city #1 residents is greater than the mean amount from city #2 residents. What are the null and alternative hypotheses? Assume that population 1 consists of amounts from city #1 levels and population 2 consists of amounts from city #2. O A. Ho: H1 SH2 H: H1 > H2 O B. Ho: H1 H2 H:H > H2 OC. Ho: H1 = H2 H: H1 # H2 D. Ho: H1 =H2 H: H1> H2 The test statistic is 1.54. (Round to two decimal places as needed.) The P-value is 0.067. (Round to three decimal places as needed.) State the conclusion for the test. A. Fail to reject the null hypothesis. There is not sufficient evidence to support the claim that the mean amount of strontium-90 from city #1 residents is greater. O B. Reject the null hypothesis. There is not sufficient evidence to support the claim that the mean amount of strontium-90 from city #1 residents is greater. O C. Reject the null hypothesis. There is sufficient evidence to support the claim that the mean amount of strontium-90 from city #1 residents is greater. O D. Fail to reject the null hypothesis. There is sufficient evidence to support the claim that the mean amount of strontium-90 from city #1 residents is greater. b. Construct a confidence interval suitable for testing the claim that the mean amount of strontium-90 from city #1 residents is greater than the mean amount from city ## residents. mBq < H1 - H2 (Round to two decimal places as needed.) mBq
Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter10: Statistics
Section10.4: Distributions Of Data
Problem 19PFA
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Transcribed Image Text:Listed in the data table are amounts of strontium-90 (in millibecquerels, or mBq, per gram of calcium) in a simple random sample of baby teeth obtained from
residents in two cities. Assume that the two samples are independent simple random samples selected from normally distributed populations. Do not assume that the
population standard deviations are equal. Complete parts (a) and (b) below.
E Click the icon to view the data table of strontium-90 amounts.
a. Use a 0.05 significance level to test the claim that the mean amount of strontium-90 from city #1 residents is greater than the mean amount from city #2 residents.
What are the null and alternative hypotheses? Assume that population 1 consists of amounts from city #1 levels and population 2 consists of amounts from city #2.
O A. Ho: H1 SH2
O B. Ho: H1 # H2
H: H1 > H2
H,: H1 > H2
D. Ho: H1 =H2
OC. Ho: H1 = H2
H H1 # H2
H: H1> H2
The test statistic is 1.54. (Round to two decimal places as needed.)
The P-value is 0.067. (Round to three decimal places as needed.)
State the conclusion for the test.
C A. Fail to reject the null hypothesis. There is not sufficient evidence to support the claim that the mean amount of strontium-90 from city #1 residents is greater.
B. Reject the null hypothesis. There is not sufficient evidence to support the claim that the mean amount of strontium-90 from city #1 residents is greater.
O C. Reject the null hypothesis. There is sufficient evidence to support the claim that the mean amount of strontium-90 from city #1 residents is greater.
O D. Fail to reject the null hypothesis. There is sufficient evidence to support the claim that the mean amount of strontium-90 from city #1 residents is greater.
b. Construct a confidence interval suitable for testing the claim that the mean amount of strontium-90 from city #1 residents is greater than the mean amount from city #2
residents.
mBq < H, - H2 < mBq
(Round to two decimal places as needed.)
OOO O
Transcribed Image Text:D. Ho: H1 H2
H:H1 > H2
al places as needed)
al places a
More Info
not suffici
ht of str
City #1
101
City #2
117
ufficient ev
trontiu
86
74
ent evider
121
100
tium-9
117
85
sufficient
stront
101
81
104
107
ting the cl
213
110
1 resic
107
111
290
108
100
133
101
291
145
209
Print
Done
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