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ll Sprint n 30% 3:33 PM Done bartleby.com = bartleby Q&A Engineering / Mechan. .. /Q&A Lib. .. is knawn that the Connethna red AB eut M F.d M FxF M -F sin 6 11 C0.042mi+0.056 mj 1 and for Force we can write F = -Fi F = -2500 N Since, force is given only in negative x-axis So, we take only x- component Step 2

ll Sprint n 30% 3:33 PM Done bartleby.com = bartleby Q&A Engineering / Mechan. .. /Q&A Lib. .. is knawn that the Connethna red AB eut M F.d M FxF M -F sin 6 11 C0.042mi+0.056 mj 1 and for Force we can write F = -Fi F = -2500 N Since, force is given only in negative x-axis So, we take only x- component Step 2

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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I received an answer for my last question and I am still a bit confused. In the solution you said that F only has a horizontal component, how did you arrive at that? The question says that F is down and to the left. 

ll Sprint n 30% 3:33 PM Done bartleby.com = bartleby Q&A Engineering / Mechan. .. /Q&A Lib. .. is knawn that the Connethna red AB eut M F.d M FxF M -F sin 6 11 C0.042mi+0.056 mj 1 and for Force we can write F = -Fi F = -2500 N Since, force is given only in negative x-axis So, we take only x- component Step 2
Transcribed Image Text:ll Sprint n 30% 3:33 PM Done bartleby.com = bartleby Q&A Engineering / Mechan. .. /Q&A Lib. .. is knawn that the Connethna red AB eut M F.d M FxF M -F sin 6 11 C0.042mi+0.056 mj 1 and for Force we can write F = -Fi F = -2500 N Since, force is given only in negative x-axis So, we take only x- component Step 2
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