What would be the specific heat of sample 1? The block’s initial temperature is 98 degrees C For each metal tested, use the equations shown below to determinused, ATwater, the temperature change of the water when it camsample, and ATsample, the temperature change of the metal samplethe water. Record your results in Table.Mwater = Mtotal - (Mcal + Msample)ATwater = Tfinal - Tcool%3DAT sample =100° C - Tfinal, if the initial temperature is actually 100°Record your results in the bottom row of Table below.sample 120.9311.9927.3°C34.4°C202.1984.49M calM water 3 1,-19.2TcoolTfinal@98M totalMsampleATwatergained by the water:Heat lost by sample = (Msample) (Csample) (ATsample) = (Mwater) (CwaterwaterCwater is the specific heat of water, which is 1.0 cal/g K.

Solution For steady flow condition mwCw∆Tw=msCs∆Ts

Answered: sample 1 20.93 M cal M water 3 , -19.2…

Engineering

Mechanical Engineering

sample 1 20.93 M cal M water 3 , -19.2 27.3°C 34.4°C 202.19 84.49 12.1" Tcool Trinal M total Msample ATwater

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Question

100%

What would be the specific heat of sample 1? The block’s initial temperature is 98 degrees C

For each metal tested, use the equations shown below to determin
used, ATwater, the temperature change of the water when it cam
sample, and ATsample, the temperature change of the metal sample
the water. Record your results in Table.
Mwater = Mtotal - (Mcal + Msample)
ATwater = Tfinal - Tcool
%3D
AT sample =
100° C - Tfinal, if the initial temperature is actually 100°
Record your results in the bottom row of Table below.
sample 1
20.93
11.99
27.3°C
34.4°C
202.19
84.49
M cal
M water 3 1,-19.2
Tcool
Tfinal
@98
M total
Msample
ATwater
gained by the water:
Heat lost by sample = (Msample) (Csample) (ATsample) = (Mwater) (Cwater
water
Cwater is the specific heat of water, which is 1.0 cal/g K.

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