blä 5Q4/A: Determine the most probablefailures, if any, in each circuit of Figurebelow, based on the indicatedmeasurements+20 V20v880vReLO knRo100 kn 10 kN10 kn182VBDC - 180REBDC= 200R210 knR21.0 knREL0 kn100 0(a)(b)Vce+10 VVcc+9 V826 VR12 knRe680 18.2 kfl 10 kN892v6.56v8,26 vDvBDC= 100R227 kBoC-120RE1.5 knR222 kn 3.3 kfnRE(c)(d)Transistor OpenОpenemitter collector problemsNoshortedabd

We will check region of transistor by given terminal voltage.

Llä: 5 Q4/A: Determine the most probable failures, if any, in each circuit of Figure below, based on the indicated measurements 880 v R 10 kfl Ro 1.0 k R 100 kn 10 kn Rc LB2 V L2v Poc - 180 R Poc 200 R2 1.0 kn 100 n * 10 kn LOkn (a) (b) Vce +10V Vec +9V 826 V R 12 kf Re 680 n 8.2 kfl 1.0 kf 892v 656 V 826 v Ov Poc 120 R 22 kn Poc 100 R2 27 kfl 1.5 ka 3.3 kf (c) (d) Transistor Open Оpen No shorted emitter collector problems a b d.

Llä: 5 Q4/A: Determine the most probable failures, if any, in each circuit of Figure below, based on the indicated measurements 880 v R 10 kfl Ro 1.0 k R 100 kn 10 kn Rc LB2 V L2v Poc - 180 R Poc 200 R2 1.0 kn 100 n * 10 kn LOkn (a) (b) Vce +10V Vec +9V 826 V R 12 kf Re 680 n 8.2 kfl 1.0 kf 892v 656 V 826 v Ov Poc 120 R 22 kn Poc 100 R2 27 kfl 1.5 ka 3.3 kf (c) (d) Transistor Open Оpen No shorted emitter collector problems a b d.

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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In the circuit given in the figure | VBE | = 0.7V, R1 = 34.65Kohm, R2 = 118.04Kohm, RC = 1.32Kohm, RE = 3.97Kohm, VCC = -12.00V, Beta = 287.00, calculate IC current with full analysis.
In the circuit given in the figure, Rk = 1.48Kohm, R1 = 7964.99Kohm, R2 = 7035.01Kohm, R3 = 2.46Kohm, R4 = 0.82Kohm, R5 = 24.08ohm, Ry = 98.63Kohm, VCC = 15.00V, VTN = 2.45V, Kn = Since 3.28(mA/V^2), C1= 6.30uF, C2=14.98uF, C3=10.96uF, calculate the lower cutoff frequency of the circuit in Hz. When making your transactions, 2 digits will be taken after the dot.
For the simple equivalent circuit of 0.017 m2 PV cell shown below, the reverse saturatoin current is I0= 4 * 10-11 A and at an insolation of 1-sun the short circuit current is Isc = 6.4 A. At 25 degrees C, find the following: a. The open circuit voltage b. The load current and the output power when the output voltage is V = 0.55 V c. The efficiency of the cell at V=0.55 V
In the circuit given in the figure VT = 25mV, | VBE | = 0.7V, R1 = 712.91Kohm, R2 = 43.27Kohm, R3 = 2.29Kohm, R4 = 0.98Kohm, VCC = 10.00V, VEE = -4.00V, VA = 10.06V, Beta = 137.00, Rs = 38.43ohm, Ry Calculate the IC current according to = 16.55Kohm, Ri, R0 and the voltage gain (V0 / V1) according to the Source by full analysis When making your transactions, 2 steps will be taken after the point. Select the closest option according to +/- 10% margin of error. There is only one correct answer to the question.
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