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Lsi Eksponensial dan gonori TBentuk lain dari e2 adalah:ex+iy = e eiy = e*(cosy + i sin y)ezContoh !e2-in =Note: cos(-0) = cos e dan sin(-0) = - sine=cos eisin 0e-i0 = cos e- i sin 0Tentukanlah hasil dari e9-e-i0 dan et0+e-i9 !16Fungsi Trigonometri Bilangan Komplekseie-e-i8sin e =2ii0COSe ee-i0rentukanlah lai dari:COsi=+iln 2) (jika et/2 i, e-in/2 -i,eln 2 - 2, e-In 2sinBuktikan sin2 z+ cos2 z 117Fungsi HiperbolikTentukan persamaan dari sin iy dan cos iy dengan menggunakanpersamaan sebelumnya!Setelah didapat persamaan di atas, baru lah di dapat fungsi yangdinamakan dengan sinus dan cosinus hiperbolik. Secara matematisdapat ditulis:e-ee2+ecosh z =2sinh z=Buktikan cosh2 z - sinh2 z = 1Tambah keterangan...18Status (Khuss)Logaritma

Question

Tentukan pembuktian dari pertanyaan yang dilingkaran biru 

Lsi Eksponensial dan gonori T
Bentuk lain dari e2 adalah:
ex+iy = e eiy = e*(cosy + i sin y)
ez
Contoh !e2-in =
Note: cos(-0) = cos e dan sin(-0) = - sine
=cos eisin 0
e-i0 = cos e- i sin 0
Tentukanlah hasil dari e9-e-i0 dan et0+e-i9 !
16
Fungsi Trigonometri Bilangan Kompleks
eie-e-i8
sin e =
2i
i0
COSe e
e-i0
rentukanlah lai dari:
COsi=
+iln 2) (jika et/2 i, e-in/2 -i,eln 2 - 2, e-In 2
sin
Buktikan sin2 z+ cos2 z 1
17
Fungsi Hiperbolik
Tentukan persamaan dari sin iy dan cos iy dengan menggunakan
persamaan sebelumnya!
Setelah didapat persamaan di atas, baru lah di dapat fungsi yang
dinamakan dengan sinus dan cosinus hiperbolik. Secara matematis
dapat ditulis:
e-e
e2+e
cosh z =
2
sinh z=
Buktikan cosh2 z - sinh2 z = 1
Tambah keterangan...
18
Status (Khuss)
Logaritma
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Lsi Eksponensial dan gonori T Bentuk lain dari e2 adalah: ex+iy = e eiy = e*(cosy + i sin y) ez Contoh !e2-in = Note: cos(-0) = cos e dan sin(-0) = - sine =cos eisin 0 e-i0 = cos e- i sin 0 Tentukanlah hasil dari e9-e-i0 dan et0+e-i9 ! 16 Fungsi Trigonometri Bilangan Kompleks eie-e-i8 sin e = 2i i0 COSe e e-i0 rentukanlah lai dari: COsi= +iln 2) (jika et/2 i, e-in/2 -i,eln 2 - 2, e-In 2 sin Buktikan sin2 z+ cos2 z 1 17 Fungsi Hiperbolik Tentukan persamaan dari sin iy dan cos iy dengan menggunakan persamaan sebelumnya! Setelah didapat persamaan di atas, baru lah di dapat fungsi yang dinamakan dengan sinus dan cosinus hiperbolik. Secara matematis dapat ditulis: e-e e2+e cosh z = 2 sinh z= Buktikan cosh2 z - sinh2 z = 1 Tambah keterangan... 18 Status (Khuss) Logaritma

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Step 1

As per norms, the first three questions are answered.To prove the required identities and compute the required exponential values

Step 2

Given identities

Given
cos(-x) cos x,sin(-x)= sinx (l)
e cosxisin x (2)
-
=cosx-isin x (3)
2 cos x= e +e*"
(2)+(3)
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Given cos(-x) cos x,sin(-x)= sinx (l) e cosxisin x (2) - =cosx-isin x (3) 2 cos x= e +e*" (2)+(3)

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Step 3

To derive cos x and sin x in terms of t...

(2) (3) 2 cos x e e
;
ee
-x
(4)
so, cos x
2
(2)-(3) 2isin.x = e - e
ee
-1x
ix
-ix
so,sinx
(5)
2i
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(2) (3) 2 cos x e e ; ee -x (4) so, cos x 2 (2)-(3) 2isin.x = e - e ee -1x ix -ix so,sinx (5) 2i

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