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M Usng the chain rule and/or product rule and take the denvative of yit) with respect to time, t 4) - 10sin(1)) (1) = 20 sin(6Xt))cos(Kt)) () = 30e" cos((1)) ye) = 40e" sin(()) co1(B(1)} Ht) - 50 sin(cos)) () - 60e " cos(2(0(0))' - 30(4) + 4) ) = 70e sin((1))

M Usng the chain rule and/or product rule and take the denvative of yit) with respect to time, t 4) - 10sin(1)) (1) = 20 sin(6Xt))cos(Kt)) () = 30e" cos((1)) ye) = 40e" sin(()) co1(B(1)} Ht) - 50 sin(cos)) () - 60e " cos(2(0(0))' - 30(4) + 4) ) = 70e sin((1))

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Using the chain rule and/or product rule and take the derivative of yt) with respect to time, t yt) - 10sin(1)) y(r) = 20 sin(Xt))cos(OXt)) () = 30e ye) = 40e " sin(0(1)) con(0(1) M) - 50 sin(cos()) M) - 60e " cos 2(0(1)* - 30M£) + 4) v) = 70e" sin() "cos(0(1)
Transcribed Image Text:Using the chain rule and/or product rule and take the derivative of yt) with respect to time, t yt) - 10sin(1)) y(r) = 20 sin(Xt))cos(OXt)) () = 30e ye) = 40e " sin(0(1)) con(0(1) M) - 50 sin(cos()) M) - 60e " cos 2(0(1)* - 30M£) + 4) v) = 70e" sin() "cos(0(1)
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