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- What is the value of K' if ∆G°' = -185J? Round to 3 decimal places. R = 8.314 J•mol-1 K-1 ∆G°' = -RTlnK' ∆G' = ∆G°' + RTlnQ'C2H4 (g) + 3 O2 (g) ⟶ 2 CO2 (g) + 2 H2O(l) What is the numerical value of Z in the equation below? delta(c02)/delta(t)= z x delta(c2h4)/delta(t)2 LiOH(s) → Li2O(s) + H2O(l) ΔH° = 379.1 kJLiH(s) + H2O(l) → LiOH(s) + H2(g) ΔH° = -111.0 kJ2 H2(g) + O2(g) → 2 H2O(l) ΔH° = -285.9 kJ Compute ΔH° in kJ for 2 LiH(s) + O2(g) → Li2O(s) + H2O(l)
- Cl(g) ΔH°f, = +121.3 kJ mol–1 Cl–(aq) ΔH°f, = –167.2 kJ mol–1 HCl(g) ΔH°f, = –92.3 kJ mol–1 HCl(aq) ΔH°f, = –167.2 kJ mol–1 Cl2(g) ΔH°f, = 0 kJ mol–1 H2O(l) ΔH°f, = –286 kJ mol–1 ClO2(g) ΔH°f, = +102.5 kJ mol–1 Cl2O(g) ΔH°f, = +80.3 kJ mol–1 O(g) ΔH°f, =+249.0 kJ mol–1 H(g) ΔH°f, =+218.2 kJ mol–1 Which material is most 'stable' at 298 K? Question 1 options: Cl2(g) Cl–(aq) Cl(g)TABLE A-V (H2) Gf= 0 kJ/mol (CO) Gf= -137.15 kJ/mol (HCHO) Gf= -113 kJ/molI got 2.71 and it says its wrong can someone explain please