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C,H,,O(s) + 6 0,(g) → 6 CO,(g) + 6 H,O() AH° = -2803.02 kJ (3) H (8)0% + MO'H %3D (8)0) (3)O + (s)Ɔ %3D AH° = -285.8 kJ using the following three equations: AH° = -285.8 kJ Calculate AH for the reaction: (3) 9 + ($)Ɔ 9 (s)°O"H?Ɔ *see back!

C,H,,O(s) + 6 0,(g) → 6 CO,(g) + 6 H,O() AH° = -2803.02 kJ (3) H (8)0% + MO'H %3D (8)0) (3)O + (s)Ɔ %3D AH° = -285.8 kJ using the following three equations: AH° = -285.8 kJ Calculate AH for the reaction: (3) 9 + ($)Ɔ 9 (s)°O"H?Ɔ *see back!

Chemistry & Chemical Reactivity
Chemistry & Chemical Reactivity
9th Edition
ISBN:9781133949640
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Chapter18: Principles Of Chemical Reactivity: Entropy And Free Energy
Section: Chapter Questions
Problem 21PS: For the reaction BaCO3(s) BaO(s) + CO2(g), rG = +219.7 kJ/mol-rxn. Using this value and other data...
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See image below. The answer I got is 

-626.58 kJ...is that correct?

C,H,,O(s) + 6 0,(g) → 6 CO,(g) + 6 H,O() AH° = -2803.02 kJ (3) H (8)0% + MO'H %3D (8)0) (3)O + (s)Ɔ %3D AH° = -285.8 kJ using the following three equations: AH° = -285.8 kJ Calculate AH for the reaction: (3) 9 + ($)Ɔ 9 (s)°O"H?Ɔ *see back!
Transcribed Image Text:C,H,,O(s) + 6 0,(g) → 6 CO,(g) + 6 H,O() AH° = -2803.02 kJ (3) H (8)0% + MO'H %3D (8)0) (3)O + (s)Ɔ %3D AH° = -285.8 kJ using the following three equations: AH° = -285.8 kJ Calculate AH for the reaction: (3) 9 + ($)Ɔ 9 (s)°O"H?Ɔ *see back!
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