Manipulate equation 3 to match the H20 part of the overall equation. What will be the new AH value? 3) H2(g) + ¿O2(g)→ H2O(g) AH = -241.8 kJ goal equation: 4NH3(g) + 502(g) → 4NO(g) + 6H2O(g) AH° = [ ? ] kJ Enter either a + or - sign AND the magnitude. Do not round. Enter

Physical Chemistry
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ISBN:9781133958437
Author:Ball, David W. (david Warren), BAER, Tomas
Publisher:Ball, David W. (david Warren), BAER, Tomas
Chapter2: The First Law Of Thermodynamics
Section: Chapter Questions
Problem 2.85E: Natural gas is mostly CH4. When it burns, the chemical reaction is CH4 g 2O2 g CO2 g 2H2O g The H...
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acellus_engine.html?ClassID=2134898241#
Manipulate equation 3 to match the H2O part
of the overall equation. What will be the new
AH value?
3) H2(g) + ¿O2(g) → H,0(g) AH = -241.8 kJ
%3D
goal equation:
4NH3(g) + 502(g) → 4NO(g) + 6H2O(g)
AH° = [ ? ] kJ
%3D
Enter either a + or - sign AND the magnitude. Do not round.
Enter
Transcribed Image Text:elp acellus_engine.html?ClassID=2134898241# Manipulate equation 3 to match the H2O part of the overall equation. What will be the new AH value? 3) H2(g) + ¿O2(g) → H,0(g) AH = -241.8 kJ %3D goal equation: 4NH3(g) + 502(g) → 4NO(g) + 6H2O(g) AH° = [ ? ] kJ %3D Enter either a + or - sign AND the magnitude. Do not round. Enter
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