Material= Lead Resistivity (Ω.m) = 22 x 10- 8 a) Calculate the conductivity of your material. Compare the conductivity of your material with conductivity of glass having a resistivity of 3.0 x 1010 Ω.m. b) Suppose that you have a cylinder that is made of your material with a length of l=20.0 cm and a crosssectional area of A=4.00x10-4 m2 . Calculate the resistance, R, of the cylinder. c) A 9.0-V battery is connected to the cylinder that is made of your material in part-b. Using Ohm’s law calculate the current passing through the material. (V=I*R I=?)
Material= Lead
Resistivity (Ω.m) = 22 x 10- 8
a) Calculate the
b) Suppose that you have a cylinder that is made of your material with a length of l=20.0 cm and a crosssectional area of A=4.00x10-4 m2 . Calculate the resistance, R, of the cylinder.
c) A 9.0-V battery is connected to the cylinder that is made of your material in part-b. Using Ohm’s law calculate the current passing through the material. (V=I*R I=?)
d) Suppose that the cylinder in part-b is cut into four equal pieces. Calculate the resistance of one piece of cylinder (which has a length of one fourth of the original length l) and compare your result with the original cylinder with length l.
Step by step
Solved in 4 steps