Meo Meo HSO. NH xylene +] NH2 Me OEt (66%) (87%) Me Me он MeO Meo Meo. POCI, NaOMe CI CI (86.4%) MEOH, A ACOH Me OMe (92.6%) Me CI (81.2%) Me CI HNO3 + H2SO, Meo. NO2 FIC Meo NO 2 (23) a KOH, DMSO Me OMe 100 °C Me OMe Pd/C, ELOH 22 (87 2%) 24 (91.3%) MeO MeO NH2 NaHa t EIOH, A, FC (74%) 14, BH3pyr Me F3C ACOH (94%) Me OMe Me OMe Me Compound 14

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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There are two instances where waste streams from reactions would need to be processed
can you identify them? 

MeO
MeO
MeO.
H.
ros'H
(66%)
xylene
NH2
Me
OEt
(87%)
Me
Me
HO.
MeO
MeO
MeO
POCI,
NaOMe
CI
CI
(86 4%)
Меон, д
(92.6%)
ACOH
Me
OMe
Me
CI
(81.2%)
Me
HNO, +
H,SO,
MeO
NO
FIC
HO
MeO
NO 2
(23)
F;C
КОН DMSO
Cl
NH.H20
Me
OMe
100 °C
Me
OMe
Pd/C. E:OH
(91.3%)
22
(87.2%)
24
MeO
MeO
NH2
N.
14. BH3pyr
Me
F3C
EIOH, A F;C
(74%)
ACOH
94%)
Me
OMe
Me
OMe
Me
Compound 14 =
Transcribed Image Text:MeO MeO MeO. H. ros'H (66%) xylene NH2 Me OEt (87%) Me Me HO. MeO MeO MeO POCI, NaOMe CI CI (86 4%) Меон, д (92.6%) ACOH Me OMe Me CI (81.2%) Me HNO, + H,SO, MeO NO FIC HO MeO NO 2 (23) F;C КОН DMSO Cl NH.H20 Me OMe 100 °C Me OMe Pd/C. E:OH (91.3%) 22 (87.2%) 24 MeO MeO NH2 N. 14. BH3pyr Me F3C EIOH, A F;C (74%) ACOH 94%) Me OMe Me OMe Me Compound 14 =
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