Methyl salicylate (oil of wintergreen) is prepared by heating salicylic acid, C, H O3, with methanol, CH3 OH. C,H, O3 + CH3OH C3 Hg O3 + H2O In an experiment, 1.30 g of salicylic acid is reacted with 14.5 g of methanol. The yield of methyl salicylate, Cs Hg O3, is 1.23 g. What is the percentage yield? Percentage yield = Submit Answer Try Another Version 6 item attempts remaining

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Chapter3: Calculations With Chemical Formulas And Equaitons
Section: Chapter Questions
Problem 3.98QP: Methyl salicylate (oil of wintergreen) is prepared by heating salicylic acid, C7H6O3, with methanol,...
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Methyl salicylate (oil of wintergreen) is prepared by heating salicylic acid, C7H6O3, with methanol, CH3 OH.
C7H, O3 + CH3OH → C3 H3 O3 + H20
In an experiment, 1.30 g of salicylic acid is reacted with 14.5 g of methanol. The yield of methyl salicylate, C3 Hg O3, is 1.23 g. What is the percentage
yield?
Percentage yield =
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Transcribed Image Text:Methyl salicylate (oil of wintergreen) is prepared by heating salicylic acid, C7H6O3, with methanol, CH3 OH. C7H, O3 + CH3OH → C3 H3 O3 + H20 In an experiment, 1.30 g of salicylic acid is reacted with 14.5 g of methanol. The yield of methyl salicylate, C3 Hg O3, is 1.23 g. What is the percentage yield? Percentage yield = Submit Answer Try Another Version 6 item attempts remaining
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