Modify following delete() function so that it takes only two arguments, first and x without trail. void delete(listPointer *first, listPointer trail, listPointer x) { if (trail) trail -> link = x -> link; else *first = (*first) -> link; free(x); }

Modify following delete() function so that it takes only two arguments, first and x without trail. void delete(listPointer first, listPointer trail, listPointer x) { if (trail) trail -> link = x -> link; else first = (*first) -> link; free(x); }

C++ Programming: From Problem Analysis to Program Design

8th Edition

ISBN:9781337102087

Author:D. S. Malik

Publisher:D. S. Malik

Chapter18: Stacks And Queues

Section: Chapter Questions

Problem 16SA

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Given the MileageTrackerNode class, complete main() to insert nodes into a linked list (using the InsertAfter() function). The first user-input value is the number of nodes in the linked list. Use the PrintNodeData() function to print the entire linked list. DO NOT print the dummy head node. Ex. If the input is: 3 2.2 7/2/18 3.2 7/7/18 4.5 7/16/18 the output is: 2.2, 7/2/18 3.2, 7/7/18 4.5, 7/16/18 #include "MileageTrackerNode.h"#include <string>#include <iostream>using namespace std; int main (int argc, char* argv[]) {// References for MileageTrackerNode objectsMileageTrackerNode* headNode;MileageTrackerNode* currNode;MileageTrackerNode* lastNode; double miles;string date;int i; // Front of nodes listheadNode = new MileageTrackerNode();lastNode = headNode; // TODO: Read in the number of nodes // TODO: For the read in number of nodes, read// in data and insert into the linked list // TODO: Call the PrintNodeData() method// to print the entire linked list //…
Using a doubly linked list class and node class, implement the following methods: Node* lastNode(void); void pushBack(string argData); void popBack(void); void pushFront(string argData); void print(void); void printReverse(void); void insertAfter(Node* argPtr); void deallocateAll(void); Node* searchFor(string argData); int size(void); Hard code a linked list (no UI) in the main to demonstrate your functions. Print forward and backward to show that the links are well-formed.
You are going to implement a program that creates an unsorted list by using a linked list implemented by yourself. NOT allowed to use LinkedList class or any other classes that offers list functions. It is REQUIRED to use an ItemType class and a NodeType struct to solve this. Use C++, please read instructions carefully and new solution only! The “data.txt” file has three lines of data 100, 110, 120, 130, 140, 150, 160 100, 130, 160 1@0, 2@3, 3@END You need to 1. create an empty unsorted list 2. add the numbers from the first line to list using putItem() function. Then print all the current keys to command line in one line using printAll(). 3. delete the numbers given by the second line in the list by using deleteItem() function. Then print all the current keys to command line in one line using printAll().. 4. putItem () the numbers in the third line of the data file to the corresponding location in the list. For example, 1@0 means adding number 1 at position 0 of the list. Then…
You are going to implement a program that creates an unsorted list by using a linked list implemented by yourself. NOT allowed to use LinkedList class or any other classes that offers list functions. It is REQUIRED to use an ItemType class and a NodeType struct to solve this homework. The “data.txt” file has three lines of data 100, 110, 120, 130, 140, 150, 160 100, 130, 160 1@0, 2@3, 3@END You need to 1. create an empty unsorted list 2. add the numbers from the first line to list using putItem() function. Then print all the current keys to command line in one line using printAll(). 3. delete the numbers given by the second line in the list by using deleteItem() function. Then print all the current keys to command line in one line using printAll().. 4. putItem () the numbers in the third line of the data file to the corresponding location in the list. For example, 1@0 means adding number 1 at position 0 of the list. Then print all the current keys to command line in one…
C++ What is the output of following function for start pointing to first node of following linked list? 1->2->3->4->5->6 void fun(Node<ItemType>* start) { if(start == nullptr) return; cout << start->getItem() << " "; if(start->getNext() != nullptr ) fun(start->getNext()->getNext()); cout << start->getItem() << " ";} eof.
Write a functionLi stNode *removeFirst( ListNode *ptr)that is passed a linked list as parameter and returns the tai l of the list: That is, itremoves the first node and returns what is left. The function should deallocate thestorage of the removed node. The function returns null ptr if the list passed to itis empty.
Write a Python code using the given function and conditions. Do not use Numpy. Use LinkedList Manipulation. Given function: def insert(self, newElement, index) Pre-condition: The list is not empty. Post-condition: This method inserts newElement at the given index of the list. If an element with the same key as newElement value already exists in the list, then it concludes the key already exists and does not insert the key. [You must also check the validity of the index].
Create a flow chart using this code: #class for nodesclass Node:def __init__(self, data=None, link=None):self.data=dataself.link=linkdef __str__(self):return str(self.data) #class for Linked listclass LinearList:def __init__(self, start=None,nodecount=0):self.start=startself.nodecount=nodecount #stores number of nodes in linked listdef addBegNode(self, value=None):#Adding nodes at beginningnode=Node(value)node.link=self.startself.start=nodeself.nodecount=self.nodecount+1 def printList(self):#traverse add display nodesptr=self.startwhile ptr:print(ptr)ptr=ptr.linkprint()def bubblesort(self):for lst in range(self.nodecount-1): #for controlling passes of Bubble Sortcurrent=self.startnxt=current.linkprevious=Nonewhile nxt: #Comparisons in passesif current.data>nxt.data:if previous==None:previous=current.linknxt=nxt.linkprevious.link=currentcurrent.link=nxtself.start=previouselse: temp=nxtnxt=nxt.linkprevious.link=current.linkprevious=temptemp.link=currentcurrent.link=nxtelse:…
A linked list is said to contain a cycle if any node is visited more than once while traversing the list. Given a pointer to the head of a linked list, determine if it contains a cycle. If it does, return 1. Otherwise, return 0. Example: head refers to the list of nodes 1 → 2 → 3 → 1 → NULL. There is a cycle where node 3 points back to node 1, so return 1. Function Description: Complete the has cycle function provided in the moodle assignment folder. It has the following parameter: • SinglyLinkedListNode pointer head: a reference to the head of the list. Returns: • int: 1 if there is a cycle or 0 if there is not. Note: if the list is empty, head will be null. Input Format: The code stub reads from stdin and passes the appropriate argument to your function. The custom test cases format will not be described for this question due to its complexity. Expand the section for the main function and review the code if you would like to figure out how to create a custom case. Constraints:…
You are given the pointer to the head node of a linked list and an integer to add to the list. Create a new node with the given integer. Insert this node at the tail of the linked list and return the head node of the linked list formed after inserting this new node. The given head pointer may be null, meaning that the initial list is empty. Function Description Complete the insertNodeAtTail function in the editor below. insertNodeAtTail has the following parameters: SinglyLinkedListNode pointer head: a reference to the head of a list int data: the data value for the node to insert Returns SinglyLinkedListNode pointer: reference to the head of the modified linked list Input Format The first line contains an integer , the number of elements in the linked list.The next lines contain an integer each, the value that needs to be inserted at tail. Constraints Sample Input STDIN Function ----- -------- 5 size of linked list n = 5 141 linked list data values…
C++ Question You need to write a class called LinkedList that implements the following List operations: public void add(int index, Object item); // adds an item to the list at the given index, that index may be at start, end or after or before the // specific element 2.public void remove(int index); // removes the item from the list that has the given index 3.public void remove(Object item); // finds the item from list and removes that item from the list 4.public List duplicate(); // creates a duplicate of the list // postcondition: returns a copy of the linked list 5.public List duplicateReversed(); // creates a duplicate of the list with the nodes in reverse order // postcondition: returns a copy of the linked list with the nodes in 6.public List ReverseDisplay(); //print list in reverse order 7.public Delete_Smallest(); // Delete smallest element from linked list 8.public List Delete_duplicate(); // Delete duplicate elements from a given linked list.Retain the…
Implement the function below void swap(int pos1, int pos2) {} Inital code to be completed: class LinkedList : public List { node* head; node* tail; int index; node* create_node(int num) { node* n = (node*) malloc(sizeof(node)); n->element = num; n->next = NULL; return n; } public: LinkedList() { index = 0; head = NULL; tail = NULL; } int add(int num) { addTail(num); return index; } int get(int pos) { node* currnode = head; int count =0; while (currnode != NULL){ count++; if (count == pos){ return currnode -> element; }else{ currnode = currnode -> next; } } return -1; } int size() { return index; } void swap(int pos1, int pos2) { } // WARNING!…