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Q-No.5: Consider the following code and write the output of this code.
(b) q = linkedlist;
while (q != NULL)
cout << q->data << " ";
q = q->next;
cout << endl;
Step by step
Solved in 2 steps with 2 images
- Assume a linked list contains following integers: 4, 2, 6, 5, 8, 3, 15 and the pointer head is pointing to the first node of the list. What will be the value of variable a after the following statements are executed: Node<int> *curNode=head; int a; curNode=curNode->getNext(); head->setNext(curNode); head=head->getNext(); a=head->getItem(); A.2 B.4 C.6 D.15In c++ , write a program to create a structure of a node, create a class Linked List. Implement all operations of a linked list as member function of this class. • create_node(int); • insert_begin(); • insert_pos(); • insert_last(); • delete_pos(); • sort(); • search(); • update(); • reverse(); • display(); ( Drop coding in words with screenshot of output as well )Assume a linked list contains following integers: 7, 2, 9, 5, 8, 3, 15 and the pointer head is pointing to the first node of the list. What will be the value of variable a after the following statements are executed: Node<int> *curNode=head; int a; while(curNode->getNext()!=NULL){ { curNode=curNode->getNext(); } a=curNode->getItem(); A. 15 B. 7 C. 49 D. 3
- Assume a linked list contains following integers: 5, 2, 4, 6, 8, 3, 15 and the pointer head is pointing to the first node of the list. What will be the value of variable a after the following statements are executed: Node<int> *curNode=head; int a=0; curNode->setNext(NULL); while(curNode!=NULL){ a+=curNode->getItem(); curNode=curNode->getNext(); } A.5 B.2 C.43 D.38int F(node<int>&p){int c=0; while(p!=0){p=p->next; c++; } return c;} This function is a. return the number of items in the linked list b. return the number of items in a linked list and destroy the linked list c. None of these d. destroy the list and free all allocated nodesAssume a linked list contains following integers: 5, 2, 4, 6, 8, 3, 15 and the pointer head is pointing to the first node of the list. What will be the value of variable a after the following statements are executed: Node<int> *curNode=head; int a=0; while(curNode!=NULL){ a+=curNode->getItem(); curNode=curNode->getNext(); if(curNode!=NULL) curNode=curNode->getNext(); } A.32 B.43 C.19 D.18
- Assume a linked list contains following integers: 7, 2, x, 5, 8, x, 15 and the pointer head is pointing to the first node of the list. What will be the value of variable a after the following statements are executed: Node<int> *curNode=head; curNode=curNode->getNext(); curNode=curNode->getNext(); int a; a=curNode->getItem(); 1. x 2. 2 3. 7 4. x+9Complete the following function where a node is perculated through a MaxHeap when given the value of the parent node (through the use of a linked list) void BinMaxHeap::percolateUp(BHNode *p) { }Assume a linked list contains following integers: 5, 2, 4, 6, 8, 3, 15 and the pointer head is pointing to the first node of the list. What will be the value of variable a after the following statements are executed: Node<int> *curNode=head; curNode=curNode->getNext(); curNode=curNode->getNext(); int a=curNode->getItem()<<endl; Group of answer choices A.4 B.2 C.5 D.6
- Assume a linked list contains following integers: 2, 2, 4, 5, 8, 3, 15 and the pointer head is pointing to the first node of the list. What will be the value of variable a after the following statements are executed: Node<int> *curNode; curNode=new Node<int>(10,head); head=curNode; int a; while(curNode!=NULL){ a+=curNode->getItem(); curNode=curNode->getNext(); } A.49 B.39 C.7 D.15Assume a linked list contains following integers: 2, 2, 4, 5, 8, 3, 15 and the pointer head is pointing to the first node of the list. What will be the value of variable a after the following statements are executed: Node<int> *curNode=head; int a=0; while(curNode->getItem()<7){ a+=curNode->getItem(); curNode=curNode->getNext(); } A. 13 B. 5 C. 8 D. 21Part2: LinkedList implementation 1. Create a linked list of type String Not Object and name it as StudentName. 2. Add the following values to linked list above Jack Omar Jason. 3. Use addFirst to add the student Mary. 4. Use addLast to add the student Emily. 5. Print linked list using System.out.println(). 6. Print the size of the linked list. 7. Use removeLast. 8. Print the linked list using for loop for (String anobject: StudentName){…..} 9. Print the linked list using Iterator class. 10. Does linked list hava capacity function? 11. Create another linked list of type String Not Object and name it as TransferStudent. 12. Add the following values to TransferStudent linked list Sara Walter. 13. Add the content of linked list TransferStudent to the end of the linked list StudentName 14. Print StudentName. 15. Print TransferStudent. 16. What is the shortcoming of using Linked List?