Introductory Chemistry: An Active Learning Approach
6th Edition
ISBN:9781305079250
Author:Mark S. Cracolice, Ed Peters
Publisher:Mark S. Cracolice, Ed Peters
Chapter4: Introduction To Gases
Section: Chapter Questions
Problem 67E: The compression ratio in an automobile engine is the ratio of the gas pressure at the end of the...
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Transcribed Image Text:oles of CO₂ = (Mass of CO₂) + (Molar Mass of CO₂)
0.489/44.01 = = 0.0
Molar Volume = VSTP + Moles of CO₂
Percent error = |
0.233/0.0111 = 20.99 L/mol
experimental value-true value
true value
True value = 22.4 L/mol
0.01119
| x 100
-22.4 20.99
22.4
- 6.29%
*100
Transcribed Image Text:ere's the second problem. You are doing an experiment in a laboratory that is 30.ºC and 1.080
atm of pressure. You take a 0.240L flask that weighs 98.005g and fill it with CO₂. After it is
filled it weighs 98.206g. Calculate the molar volume of the CO₂!
VSTP =
P₁V₁T STP
T1PSTP
1.080 * 0.240* 273
303*1
= 0.233L
1.200 * 0.240 =
0.2889
0.4899
98-206-98-005 +0.288 = 0.4
0.489/44.81 = 0.0111mol.com
0-233/0.0111 = 20.99 L/mol
Mass of air = (density of air)(volume of flask)
1.200 * 0.240 = 0.
0.2889
Mass of CO₂ = (Mass of flask filled with CO₂) - (Mass of empty flask) + (Mass of air)
92-206-98·005 +0.288 = 0
0.4899
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