   Chapter 10, Problem 4PS

Chapter
Section
Textbook Problem

Put the following in order of increasing pressure: 363 mm Hg, 363 kPa, 0.256 atm, and 0.523 bar.

Interpretation Introduction

Interpretation:

The given pressures should be arranged in their increasing order.

Concept Introduction:

Pressure=ForceArea

Pressure can be expressed in different units. But it is normally reported in mmHg(millimetersofmercury)

General unit conversions:

1atm=760mmHg1pascal=1newton/meter21atm=760mmHg=101.325kilopascals=1.01325bar1bar=1×105pascal

Explanation

Given the values of pressure as 363mmHg,363kPa,0.256atm,0.523bar

• Pressure =363mmHg
• Conversion of kPa into mmHg:

Giventhatpressure=363kPa760mmHg=101.325kilopascals

363kPa×760mmHg101.3kPa=2723.3mmHg

• Conversion of atmintommHg.

Giventhatpressure=0.256atm

1atm=760mmHg0.256atm×760mmHg1atm=194.56mmHg

• Conversion of barintommHg

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