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mole of particle A and 0.792 mole of particle B and both particles are accelerated to 5.73 MeV. What is the energy in terms of kJ/mole for particle A? Hint: 1 MeV = 1 x 10^6 eV and 1 eV = 1.602 x 10^-19 J and 1 kJ = 1000 J, and finally in 1 mole there are Avogrado's number of particles which is 6.02314 x 10^23 particles/mole

mole of particle A and 0.792 mole of particle B and both particles are accelerated to 5.73 MeV. What is the energy in terms of kJ/mole for particle A? Hint: 1 MeV = 1 x 10^6 eV and 1 eV = 1.602 x 10^-19 J and 1 kJ = 1000 J, and finally in 1 mole there are Avogrado's number of particles which is 6.02314 x 10^23 particles/mole

Introductory Chemistry: An Active Learning Approach
Introductory Chemistry: An Active Learning Approach
6th Edition
ISBN:9781305079250
Author:Mark S. Cracolice, Ed Peters
Publisher:Mark S. Cracolice, Ed Peters
Chapter20: Nuclear Chemistry
Section: Chapter Questions
Problem 43E
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In the following nuclear equation what particle is A & B

also if possible what is the energy for particle A. 

suppose there was a release of 0.572 mole of particle A and 0.792 mole of particle B and both particles are accelerated to 5.73 MeV. What is the energy in terms of kJ/mole for particle A? Hint: 1 MeV = 1 x 10^6 eV and 1 eV = 1.602 x 10^-19 J and 1 kJ = 1000 J, and finally in 1 mole there are Avogrado's number of particles which is 6.02314 x 10^23 particles/mole

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